gpt4 book ai didi

java - 使用 Java API 的 Neo4j Cypher Query 1.9.6 问题

转载 作者:行者123 更新时间:2023-12-02 06:05:04 25 4
gpt4 key购买 nike

我正在使用以下查询

     START n=node(*)
MATCH(n)
WHERE n.Gender ?="Female"
RETURN n

在服务器中完美运行。

我的程序如下

    void query()
{
ExecutionResult result,;
Transaction tx=null;
ExecutionEngine engine = new ExecutionEngine( graphDb );

try
{
String name="Female";
tx=graphDb.beginTx();
result=engine.execute("start n=node(*)match(n)where n.Gender ?={Female} return n");
System.out.println(result.dumpToString());
tx.success();
}

catch(Exception e)
{
try
{
File f=new File("trace.txt");
BufferedWriter br=new BufferedWriter(new FileWriter(f,true));
tx.failure();
k=Arrays.toString(e.getStackTrace());
System.out.println(k);
br.write(k);
br.close();
throw new IOException();
}
catch (Exception ex)
{
}
}
finally
{
tx.finish();
}

}

当我尝试通过程序执行它时,它会进入 catch block 并打印以下堆栈跟踪

            [org.neo4j.cypher.internal.pipes.QueryState$$anonfun$getParam$1.apply(QueryState.scala:60),
org.neo4j.cypher.internal.pipes.QueryState$$anonfun$getParam$1.apply(QueryState.scala:60),
scala.collection.MapLike$class.getOrElse(MapLike.scala:128),
scala.collection.AbstractMap.getOrElse(Map.scala:58),
org.neo4j.cypher.internal.pipes.QueryState.getParam(QueryState.scala:60),
org.neo4j.cypher.internal.commands.expressions.ParameterExpression.apply(ParameterExpression.scala:27),
org.neo4j.cypher.internal.commands.Equals.isMatch(ComparablePredicate.scala:59),
org.neo4j.cypher.internal.commands.NullablePredicate.isMatch(Predicate.scala:59),
org.neo4j.cypher.internal.pipes.FilterPipe$$anonfun$internalCreateResults$1.apply(FilterPipe.scala:30),
org.neo4j.cypher.internal.pipes.FilterPipe$$anonfun$internalCreateResults$1.apply(FilterPipe.scala:30),
scala.collection.Iterator$$anon$14.hasNext(Iterator.scala:390),
org.neo4j.cypher.internal.ClosingIterator$$anonfun$next$1.apply(ClosingIterator.scala:45),
org.neo4j.cypher.internal.ClosingIterator.failIfThrows(ClosingIterator.scala:86),
org.neo4j.cypher.internal.ClosingIterator.next(ClosingIterator.scala:43),
scala.collection.Iterator$class.foreach(Iterator.scala:727),
org.neo4j.cypher.internal.ClosingIterator.foreach(ClosingIterator.scala:31),
scala.collection.generic.Growable$class.$plus$plus$eq(Growable.scala:48),
scala.collection.mutable.ListBuffer.$plus$plus$eq(ListBuffer.scala:178),
scala.collection.mutable.ListBuffer.$plus$plus$eq(ListBuffer.scala:45),
scala.collection.TraversableOnce$class.to(TraversableOnce.scala:259),
org.neo4j.cypher.internal.ClosingIterator.to(ClosingIterator.scala:31),
scala.collection.TraversableOnce$class.toList(TraversableOnce.scala:243),
org.neo4j.cypher.internal.ClosingIterator.toList(ClosingIterator.scala:31),
org.neo4j.cypher.PipeExecutionResult.eagerResult(PipeExecutionResult.scala:100),
org.neo4j.cypher.PipeExecutionResult.dumpToString(PipeExecutionResult.scala:103),
org.neo4j.cypher.PipeExecutionResult.dumpToString$lzycompute(PipeExecutionResult.scala:143),
org.neo4j.cypher.PipeExecutionResult.dumpToString(PipeExecutionResult.scala:140),
org.neo4j.cypher.javacompat.ExecutionResult.dumpToString(ExecutionResult.java:102),
Neo4jQuery.query(Neo4jQuery.java:90), Neo4jQuery.main(Neo4jQuery.java:35),
__SHELL3.run(__SHELL3.java:6), sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method),
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57),
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43),
java.lang.reflect.Method.invoke(Method.java:606), bluej.runtime.ExecServer$3.run(ExecServer.java:725)]

我认为我以错误的方式传递了参数“female”。

最佳答案

首先我应该说我不熟悉 Neo4j 的 Java API。但据我所见:

在密码中

MATCH (n)

不正确。您需要描述完整路径,例如 MATCH (n)-->(m)MATCH (n)-[:friend_of]-(m),或跳过匹配条款全部放在一起。在您的特定示例中,您不需要 match 子句,因此您可以跳过它。

第二件事是 - 是的,您没有正确传递参数 - 您可以在此处查看一些有关如何将参数传递给 ExecutionEgine 的示例: http://docs.neo4j.org/chunked/stable/tutorials-cypher-parameters-java.html

在您的示例中,您可以执行以下操作:

void query() {
ExecutionResult result,;
Transaction tx=null;
ExecutionEngine engine = new ExecutionEngine( graphDb );

try
{
Map<String, Object> params = new HashMap<String, Object>();
params.put("gender", "Female");
tx=graphDb.beginTx();
result = engine.execute("start n=node(*) where n.Gender ?= {gender} return n",params);
System.out.println(result.dumpToString());
tx.success();
}
catch(Exception e)
{
try
{
File f=new File("trace.txt");
BufferedWriter br=new BufferedWriter(new FileWriter(f,true));
tx.failure();
k=Arrays.toString(e.getStackTrace());
System.out.println(k);
br.write(k);
br.close();
throw new IOException();
}
catch (Exception ex)
{
}
}
finally
{
tx.finish();
}

}

关于java - 使用 Java API 的 Neo4j Cypher Query 1.9.6 问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22357049/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com