java - 如何在java中匹配紧邻的前一个单词模式？

Question

我有一个像这样的字符串:

"value of <abc/def> ends with <def> and value of <abc/def> does not end with <abc> and value of <abc> is <abc>"

我想提取字符串value of <abc/def> does not end with <abc> 。
我使用了以下模式

String text = "value of <abc/def> ends with <def> and value of <abc/def> does not end with <abc> and value of <abc> is <abc>";
String patternString1 = "(value\\s+of\\s+(<.*>)\\s+ends\\s+with\\s+(<.*>))";
Pattern pattern = Pattern.compile(patternString1);
Matcher matcher = pattern.matcher(text);
while(matcher.find()) {
    System.out.println("found: " + matcher.group(1));
}

结果:-

found: value of <abc/def> ends with <def> and value of <abc/def> does not end with <abc> and value of <abc> is <abc>

Answer 1

正如你的意思是得到 value of <abc/def> does not end with <abc>修正后的图案:

String patternString1 = "(value\\s+of\\s+(<[^>]*>)\\s+does\\s+not\\s+end\\s+with\\s+(<[^>]*>))";