java - JSON 与 pretty-print

Question

我用java制作了一个JSONObject，并尝试使用gson的 pretty-print 功能来使该对象在网站上更具可读性，但它一直显示为；

{"后门":"已解锁","窗口 2":"已解锁","窗口 3":"已解锁","窗口 1":"已解锁","前门":"已解锁","系统":"撤防","灯":"开"}

这是我迄今为止使用 gson-2.2.4-javadoc.jar、gson.2.2.4-sources.jar 和 gson.2.2.4 jar 文件得到的代码；

import com.google.gson.Gson;
import com.google.gson.GsonBuilder;

@Get("json")
public String handleGet() {
    try {
        JSONObject system = new JSONObject();

        system.put("System", "Disarmed");
        system.put("Front Door", "Unlocked");
        system.put("Back Door", "Unlocked");
        system.put("Window 1", "Unlocked");
        system.put("Window 2", "Unlocked");
        system.put("Window 3", "Unlocked");
        system.put("Lights", "On");

        Gson gson = new GsonBuilder().setPrettyPrinting().create();
        System.out.println( gson.toJson(system) );

        JsonRepresentation jsonRep = new JsonRepresentation(system);

        return jsonRep.getText();
    } catch (JSONException e) {
        e.printStackTrace();
    } catch (IOException e)
    {
        e.printStackTrace();
    }
    return null;
}

编辑

像这样编辑代码后；

Gson gson = new GsonBuilder().setPrettyPrinting().create();
System.out.println( gson.toJson(system) );

//JsonRepresentation jsonRep = new JsonRepresentation(system);

String pretty = gson.toJson(system);
return pretty;

//return jsonRep.getText();

} catch (JSONException e) {
e.printStackTrace();
//} catch (IOException e)
{
e.printStackTrace();
}
return null;
}
}

现在它显示为；

{
  "map": {
    "Back Door": "Unlocked",
    "Window 2": "Unlocked",
    "Window 3": "Unlocked",
    "Window 1": "Unlocked",
    "Front Door": "Unlocked",
    "System": "Disarmed",
    "Lights": "On"
  }
}

有什么办法可以将“ map ”更改为“系统”吗？

Answer 1

只需返回打印精美的 Gson 输出

String pretty = gson.toJson(system);
return pretty;

有这个值

{
  "Lights": "On",
  "Front Door": "Unlocked",
  "Window 3": "Unlocked",
  "Window 2": "Unlocked",
  "System": "Disarmed",
  "Back Door": "Unlocked",
  "Window 1": "Unlocked"
}