azure - 如何在Azure DevOps中编译.NET(控制台应用程序)并生成exe

Question

我使用 .NET 桌面模板并使用“create .msi”扩展创建了一个管道，但它显示了一条警告:

 ##[warning]No .MSI files were found, please check your build-configuration. If this is expected, you might consider to use the default Visual Studio Build task instead of this custom Installer task.
2018-11-28T22:58:54.1434410Z ##[section]Finishing: Create .msi file(s) from VS Installer project(s).

任何人都知道如何使用 Azure Pipeline 创建 exe 文件并将其部署在虚拟机上。

Answer 1

If you use .NET Core CLI task to build your console app.

下面的 dotnetpublisharguments 命令将生成 .exe 文件。请参阅this thread了解更多信息。

dotnet publish -r win-x64 -p:PublishSingleFile=True --self-contained false

因此，您可以将上述参数添加到 .NET Core CLI 任务中。请参阅下面的 yaml 管道。

- task: DotNetCoreCLI@2
  inputs:
    command: publish 
    arguments: -r win-x64 -p:PublishSingleFile=True --self-contained false -o $(Build.ArtifactStagingDirectory)
    projects: '**/*.csproj'
    publishWebProjects: false
  enabled: true

上述DotNetCoreCLI任务将把.exe文件输出到文件夹$(Build.ArtifactStagingDirectory) (即 C:\agent\_work\1\a )

If you use Visual Studio Build task to build your console app.

您可以先在下面添加<PublishSingleFile>和<RuntimeIdentifier>属性添加到项目的 .csproj 文件中。

<PropertyGroup>
    <OutputType>Exe</OutputType>
    <TargetFramework>netcoreapp3.1</TargetFramework>
    <PublishSingleFile>True</PublishSingleFile>
    <RuntimeIdentifier>win-x64</RuntimeIdentifier>
  </PropertyGroup>

然后在管道中设置 Visual Studio 生成任务的 msbuildArgs，如下所示:

- task: VSBuild@1
  inputs:
    solution: '$(solution)'
    platform: '$(buildPlatform)'
    configuration: '$(buildConfiguration)'
    msbuildArgs: '/t:publish /p:PublishSingleFile=True /p:RuntimeIdentifier=win-x64 /p:outputpath=$(Build.ArtifactStagingDirectory)\'

然后Vsbuild任务会将.exe文件输出到文件夹$(Build.ArtifactStagingDirectory) /p:outputpath 中指定(即 C:\agent\_work\1\a )