java - 如何将扫描仪编号传递给 ArrayList

Question

我的方法运行良好!我试图从用户那里获取信息，而不是像我在代码中那样自己输入数字。有没有一种方法可以让我传递数字而不将它们存储在不同的变量中!谢谢。

import java.util.*;

public class Interleave {
    public static void main(String[] args) {
        Scanner console = new Scanner(System.in);
        System.out.println("Welcome to Interleave program! ");
        System.out.println();


        System.out.print("how many number for array 1:= ");
        int array1 = console.nextInt();
        for (int i = 0; i < array1; i++) {
            System.out.print("please enter nubmers := ");
            int num = console.nextInt();
        }

        ArrayList<Integer> a1 = new ArrayList<Integer>();
        a1.add(10);
        a1.add(20);
        a1.add(30);

        System.out.println();
        System.out.print("how many number for array 2:= ");
        int array2 = console.nextInt();
        for (int i = 0; i < array2; i++) {
            System.out.print("please enter nubmers := ");
            int num2 = console.nextInt();
        }

        ArrayList<Integer> a2 = new ArrayList<Integer>();
        a2.add(4);
        a2.add(5);
        a2.add(6);
        a2.add(7);
        a2.add(8);

        System.out.println();
        System.out.println(a1);
        System.out.println(a2);

        interleave(a1, a2); //parameters

        System.out.println(a1);


    }//end of main
    public static void interleave(ArrayList<Integer> list1, ArrayList<Integer> list2) {
        int sizeList1 = list1.size();//size of array
        int sizeList2 = list2.size();//size of array

        ArrayList<Integer> temp = new ArrayList<Integer>(); //


        for (int index = 0; index < list1.size(); index++)// copy elements ferom list 1
            temp.add(index, list1.get(index));


        for (int index = 0; index < list2.size(); index++)// copy elements ferom list 2
            temp.add(index, list2.get(index));


        int tempSize = temp.size(); //get temporary array size

        temp.clear(); //clear tepm array


        if (list1.size() > list2.size()) {
            for (int index = 0, list1Index = 0, list2Index = 0;
            index < sizeList1;
            index = index + 2, list1Index++, list2Index++ )
            {
                temp.add(index, list1.get(list1Index));
                temp.add(index + 1, list2.get(list2Index));
            }


            for (int index = 2 * list2.size(),
            list2Count = list2.size();
            index < tempSize; list2Count++, index++ )
            temp.add(index, list1.get(list2Count));

            list1.clear(); // clear list 1

            for (int index = 0; index < temp.size(); index++)
                list1.add(index, temp.get(index));
        } else {
            for (int index = 0, list1Index = 0, list2Index = 0;
            index < sizeList2;
            index = index + 2, list1Index++, list2Index++ )
            {
                temp.add(index, list1.get(list1Index));
                temp.add(index + 1, list2.get(list2Index));
            }

            for (int index = 2 * list1.size(),
            list1Count = list1.size(); index < tempSize;
            list1Count++, index++ )
            temp.add(index, list2.get(list1Count));


            list1.clear();

            for (int index = 0; index < temp.size(); index++)
                list1.add(index, temp.get(index));
        }


    }//end of interleave


}//end of class

Answer 1

1. 创建整数 ArrayList
2. 每次需要添加号码时，请调用 mylist.add(console.nextInt())
3. 完成后调用 mylist.clear()，或将其设置为新的 ArrayList。

请注意可能引发的各种异常并 try catch 它们，以便用户必须重新输入数字直到其有效。