Java基于textField对arrayList进行排序

Question

背景:我正在创建此员工记录应用程序，您可以在其中添加人员 ID、名字、姓氏、工资和开始日期。它由“添加”按钮、“删除”按钮、“列表”组合框和一个输出组成。

我需要帮助的是按 ID 对 arrayList 进行排序并在输出中显示排序后的版本。 `公共(public)类 EmployeeRecordsView 扩展了 FrameView{

    ArrayList <one> myList = new ArrayList <one>();
    //List<one> records = new ArrayList<one>();
    String iD, first, last, salary, startDate;
    public EmployeeRecordsView(SingleFrameApplication app) {
      //Cut out code
    }

    class one {
        String iD, first, last, salary, startDate;
        one (String _iD, String _first, String _last, String _salary, String
        _startDate){
            iD = _iD;
            first = _first;
            last = _last;
            salary = _salary;
            startDate = _startDate;
        }
    }
    private void btnAddMouseClicked(java.awt.event.MouseEvent evt) {                                    
       one emp;
       iD = id.getText();
       first = firstName.getText();
       last = lastName.getText();
       salary = sal.getText();
       startDate = start.getText();
       emp = new one(iD, first, last, salary, startDate);
       myList.add(emp);
    }                                   

    private void btnRemoveMouseClicked(java.awt.event.MouseEvent evt) {                                       
        String remove;
        remove = id.getText();
        myList.remove(remove);
    }                                      

    private void btnExitMouseClicked(java.awt.event.MouseEvent evt) {                                     
        System.exit(0);
    }                                    


    private void jComboBox1MouseClicked(java.awt.event.MouseEvent evt) {
     if (jComboBox1.getSelectedItem() == "Order of Addition"){
            String temp="";

        for (int x=0; x<=myList.size()-1; x++) {
            temp = temp + "ID#: " + myList.get(x).iD + ", "
                    + "First Name: " + myList.get(x).first + ", "
                    + "Last Name: " + myList.get(x).last + ", "
                    + "Annual Salary: " + myList.get(x).salary + ", "
                    + "Starting Date: " + myList.get(x).startDate + "\n";
        }
        outPut.setText(temp);
        }

     if (jComboBox1.getSelectedItem() == "ID"){
         String temp="";
        for (int x=0; x<=myList.size()-1; x++) {
                  temp = temp + "ID#: " + myList.get(x).iD + ", "
                    + "First Name: " + myList.get(x).first + ", "
                    + "Last Name: " + myList.get(x).last + ", "
                    + "Annual Salary: " + myList.get(x).salary + ", "
                    + "Starting Date: " + myList.get(x).startDate + "\n";
        }
        outPut.setText(temp);
     }`
    }

Answer 1

使用Collections.sort(List, Comparator) ，这将允许您通过使用Comparator以自定义方式对List进行排序。

因此，根据对一个类的轻微修改，添加一个 getter 来检索iD值

class One {

    String iD, first, last, salary, startDate;

    One(String _iD, String _first, String _last, String _salary, String _startDate) {
        iD = _iD;
        first = _first;
        last = _last;
        salary = _salary;
        startDate = _startDate;
    }

    public String getID() {
        return iD;
    }
}

你可以使用...

Collections.sort(myList, new Comparator<One>() {
    @Override
    public int compare(One o1, One o2) {
        return o1.getID().compareTo(o2.getID());
    }
});

现在请注意，这将以自然顺序对 ID 进行排序，即 1 不会出现在 10 之前，这就是 String 排序的方式有效...