php - 从 Laravel 4 中的事务中返回数据

Question

我有以下代码片段，但似乎无法正常工作。

$paymentGatewayTransaction = $this->processTransaction($data);
DB::connection('new_db')->transaction(function () use ($paymentGatewayTransaction) {
    //Performing all DB transactions here to insert Order Information.
    if ($paymentGatewayTransaction['Status'] == "APPROVED")
        return Response::json(array('Status' => 'Success'), '200'); else
        return Response::json(array('Status' => 'Error'), '200');
});

function processTransaction($data) {
    //Process Gateway Transaction
    if ($gatewayWasSuccessfull)
        return array('Status' => 'APPROVED'); else
        return array('Status' => 'DECLINED');
}

返回 Response::json() 行 5和 7似乎根本没有任何影响。响应永远不会到达浏览器。

如果我从行 4 移动 if 条件直通 8在闭包函数之外，它工作正常。

作为解决方法，我最终不得不执行以下操作。

$paymentGatewayTransaction = $this->processTransaction($data);
$orderObj = "";
DB::connection('new_db')->transaction(function () use ($paymentGatewayTransaction, &$orderObj) {
    //Performing all DB transactions here to insert Order Information.
    // **$orderObj is set here**
});

if ($paymentGatewayTransaction['Status'] == "APPROVED")
    return Response::json(array('Status' => 'Success', 'Order' => $orderObj->id), '200'); else
    return Response::json(array('Status' => 'Error'), '200');

function processTransaction($data) {
    //Process Gateway Transaction
    if ($gatewayWasSuccessfull)
        return array('Status' => 'APPROVED'); else
        return array('Status' => 'DECLINED');
}

创建对象 $orderObj在闭包之外，并通过引用事务将其作为变量，以便在闭包函数之外使用它。这可以更简单还是这是使用它的方法？

Answer 1

您可以在变量中分配事务关闭的返回值，如下所示:

$paymentGatewayTransaction = $this->processTransaction($data);
$var = DB::connection('new_db')->transaction(function () use ($paymentGatewayTransaction) {
    //Performing all DB transactions here to insert Order Information.
    if ($paymentGatewayTransaction['Status'] == "APPROVED")
        return Response::json(array('Status' => 'Success'), '200'); else
        return Response::json(array('Status' => 'Error'), '200');
});
return $var;

然后你可以使用 $var 返回。