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PHP上传多个文件只上传1个文件

转载 作者:行者123 更新时间:2023-12-02 05:50:45 28 4
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我多次编辑此代码(我是 php 新手)我的问题是使用此代码上传多个文件。我只能上传 1 个文件。

代码如下:

<?php
/**
* uploadFile()
*
* @param string $file_field name of file upload field in html form
* @param bool $check_image check if uploaded file is a valid image
* @param bool $random_name generate random filename for uploaded file
* @return array
*/
function uploadFile ($file_field = null, $check_image = false, $random_name = false) {

//Config Section
//Set file upload path
$path = 'c:/xampp/htdocs/'; //with trailing slash
//Set max file size in bytes
$max_size = 1000000;
//Set default file extension whitelist
$whitelist_ext = array('jpg','png','gif');
//Set default file type whitelist
$whitelist_type = array('image/jpeg', 'image/png','image/gif');

//The Validation
// Create an array to hold any output
$out = array('error'=>null);

if (!$file_field) {
$out['error'][] = "Please specify a valid form field name";
}

if (!$path) {
$out['error'][] = "Please specify a valid upload path";
}

if (count($out['error'])>0) {
return $out;
}

//Make sure that there is a file
if((!empty($_FILES[$file_field])) && ($_FILES[$file_field]['error'] == 0)) {

// Get filename
$file_info = pathinfo($_FILES[$file_field]['name']);
$name = $file_info['filename'];
$ext = $file_info['extension'];

//Check file has the right extension
if (!in_array($ext, $whitelist_ext)) {
$out['error'][] = "Invalid file Extension";
}

//Check that the file is of the right type
if (!in_array($_FILES[$file_field]["type"], $whitelist_type)) {
$out['error'][] = "Invalid file Type";
}

//Check that the file is not too big
if ($_FILES[$file_field]["size"] > $max_size) {
$out['error'][] = "File is too big";
}

//If $check image is set as true
if ($check_image) {
if (!getimagesize($_FILES[$file_field]['tmp_name'])) {
$out['error'][] = "Uploaded file is not a valid image";
}
}

//Create full filename including path
if ($random_name) {
// Generate random filename
$tmp = str_replace(array('.',' '), array('',''), microtime());

if (!$tmp || $tmp == '') {
$out['error'][] = "File must have a name";
}
$newname = $tmp.'.'.$ext;
} else {
$newname = $name.'.'.$ext;
}

//Check if file already exists on server
if (file_exists($path.$newname)) {
$out['error'][] = "A file with this name already exists";
}

if (count($out['error'])>0) {
//The file has not correctly validated
return $out;
}

if (move_uploaded_file($_FILES[$file_field]['tmp_name'], $path.$newname)) {
//Success
$out['filepath'] = $path;
$out['filename'] = $newname;
return $out;
} else {
$out['error'][] = "Server Error!";
}

} else {
$out['error'][] = "No file uploaded";
return $out;
}
}
?>
<?php
if (isset($_POST['submit'])) {
$file = uploadFile('file', true, true);
if (is_array($file['error'])) {
$message = '';
foreach ($file['error'] as $msg) {
$message .= '<p>'.$msg.'</p>';
}
} else {
$message = "File uploaded successfully";
}
echo $message;
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input name="file" type="file" size="20" multiple="multiple" />
<input name="submit" type="submit" value="Upload files" />
</form>

请帮助我理解...我知道我必须使用foreach

最佳答案

你应该像 file[] 这样的数组来使用文件字段

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
<input name="file[]" type="file" size="20" multiple="multiple" />
<input name="submit" type="submit" value="Upload files" />
</form>

如上修改代码试试

关于PHP上传多个文件只上传1个文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17462192/

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