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java - Java 中无法访问的代码

转载 作者:行者123 更新时间:2023-12-02 05:45:33 25 4
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我不明白“无法​​访问的代码”是什么意思?

在我的代码的最后一行doubleprobabilityOfWin=wins/(wins+loses);它表示无法访问代码。

import java.util.Random;

public class CrapsGame {
public static final int GAMES = 9999;

public static void main(String[] args) {
Random randomGenerator1 = new Random();
Random randomGenerator2 = new Random();
Random randomGenerator3 = new Random();
Random randomGenerator4 = new Random();

int dice1 = randomGenerator1.nextInt(6) + 1;
int dice2 = randomGenerator2.nextInt(6) + 1;

int comeoutSum = dice1 + dice2;
int point = 0;

// The comeout roll

if (comeoutSum == 7 || comeoutSum == 12)
System.out.println("wins");
else if ( comeoutSum == 2 || comeoutSum == 3 || comeoutSum == 12)
System.out.println("loses");
else
point = comeoutSum;

int wins = 0;
int loses = 0;


while(GAMES <= 9999)
{
dice1 = randomGenerator3.nextInt(6) + 1;
dice2 = randomGenerator4.nextInt(6) + 1;
int sum = dice1 + dice2;

if (sum == point)
wins++;
else if (sum == 7)
loses++;
}

double probabilityOfWin = wins / (wins + loses);


}

}

最佳答案

这里循环:

while(GAMES <= 9999)
{
...
}

解析为while (true),因为GAMES的值从未被修改。因此,后面的任何代码(在您的情况下,doubleprobabilityOfWin=wins/(wins+loses);)都被视为无法访问

关于java - Java 中无法访问的代码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24101775/

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