java - 如何在不知道 key 的情况下使用java解析JSON对象？

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在下面JSON我想在不知道键名称的情况下解析对象。对象中还包含另一个对象。

{"status":"ok","description":"Request was successful.","account":{"renewal_upper_limit":0,"id":10066,"email":"raj@gmail.com","full_name":" Raj","phone":"99000000","format_time":"America","format_date":"Asia","reports_time_range":"24 hours","dashboard_time_range":"24H"}}

Answer 1

Json 对象就像一个 Map，你可以像这样迭代它:

    JSONObject parse = JSON.parseObject("");
    for (Map.Entry<String, Object> entry : parse.entrySet()) {
        System.out.println(entry.getKey() + "=" + entry.getValue());
    }

fastjson 可在此处获取:https://github.com/alibaba/fastjson