django - 如何在 django 中将图像从 imagefield 显示到模板

Question

我的模板无法显示来 self 的模型的图像。

src 属性带有正确的字段，但它不显示正确的图像

模板:

       <div class="grid-product">
  
    {% for p in prod %}
    
    
    <div class="  product-grid">
        <div class="content_box"><a href="single.html">
        <div class="left-grid-view grid-view-left">
             <img  class="img-responsive watch-right" alt="not found" src="{{p.photo}}"/>
                <div class="mask">
                    <div class="info">Quick View</div>
                </div>
              </a>
        </div>
            <h4><a href="#"></a></h4>
             <p>It is a long established fact that a reader{{ p.p_name }}</p>
             Rs. 499
        </div>
   </div>
    {% endfor %} 
         <div id="show"></div>
    <div class="clearfix"> </div>
</div>

型号:

class product(models.Model):
    p_id=models.AutoField(primary_key=True)
    ps_id=models.ForeignKey(alphasubcat,on_delete=models.CASCADE)
    p_name=models.CharField(max_length=100,null=True,blank=True)
    photo = models.ImageField(upload_to='productimage',blank=True)
    price=models.IntegerField()
    def __str__(self):
        return self.p_name

查看:

def produc(request):
    param=dict()
    cat=categories.objects.all()
    sub=subcategories.objects.all()
    temp=request.GET['p']
    prod=product.objects.filter(ps_id=alphasubcat.objects.get(as_name=temp))
    param['prod']=prod
    param['cat']=cat
    param['sub']=sub
    return render(request,"product.html",param)

Answer 1

您可以通过{{p.photo.url}}访问图片url。但正如您的模型中所示:

photo = models.ImageField(upload_to='productimage, blank=True)

(blank=True) 你会想要使用类似的东西:

<img  class="img-responsive watch-right" alt="not found" src={% if p.photo %}"{{p.photo.url}}"{% else %}"/something/else.png"{% endif %}/>