java - Java中如何统计字符串中辅音的个数？

Question

我正在编写一个程序，用于计算用户输入的句子中元音和辅音的数量。我下面的代码计算了元音的数量，但它给了我奇怪的辅音计数。例如，如果我输入“g”，我得到的辅音计数为 10。

import java.util.Scanner;

public class VowelCount{
  public static void main(String[] args){
    Scanner scan = new Scanner(System.in);
    System.out.print("Enter a sentence :");
    String sentence = scan.nextLine();

    String vowels = "aeiouAEIOU";
    int vowelCount = 0;
    int consCount = 0;
    int i;

      for(i = 0; i < sentence.length(); i += 1){
        char currentChar = sentence.charAt(i);
        int index;
        for(index = 0; index < vowels.length(); index += 1){
          if(vowels.charAt(index) == (currentChar)){
            vowelCount++;
          }else if(Character.isLetter(currentChar) && (vowels.charAt(index) == (currentChar))){
            consCount++;
          }
        }
      }
      System.out.println(consCount);
      System.out.println(vowelCount);
  }   
}

Answer 1

这有效。我还对其进行了改进，请参阅 vowels.indexOf (而不是手动迭代)以及带有 isLetter 的行(更正了对元音的错误检查)和输出(添加了 ; )和i++。

public class VowelCount{
  public static void main(String[] args){
    Scanner scan = new Scanner(System.in);
    System.out.print("Enter a sentence :");
    String sentence = scan.nextLine();

    String vowels = "aeiouAEIOU";
    int vowelCount = 0;
    int consCount = 0;
    int i;

    int length = sentence.length();
    for(i = 0; i < length; i ++){
        char currentChar = sentence.charAt(i);
        if (vowels.indexOf(currentChar)>=0)
           vowelCount++;
        else if(Character.isLetter(currentChar))
                consCount++;
    }
    System.out.print(consCount+";");
    System.out.print(vowelCount);
  }
}