php - 如何在 Laravel 5.0 中获取 $request->content？

Question

我是 Laravel 的新手，在获取我发布到我正在编写的 REST api 的 JSON 时遇到了一些问题。

更新为清楚起见，这是:

    $content = json_decode($request->content);
    var_dump($content);
    exit;

同时返回null

原创

这是我的store 方法:

public function store(Request $request)
{       
    // Creates a new user based on the passed JSON
    // I appreciate this wont work as it's json encoded, but this was my
    // last test. 
    // Previously I'd tried: $content = json_decode($request->content);
    // but that was also null :(
    $user = new User();
    $user->name = $request->content["name"];
    $user->email = $request->content['email'];
    $user->password = $request->content['password'];

    var_dump($request); exit;
    // Commit to the database
    $user->save();
}

这是我要发送的内容(通过:我只是休息客户端):

{
  "name":"Steve Jobs 2",
  "email":"s@trp2.com",
  "password":"something123",
}

下面是将 var_dump 作为响应呈现时的结果:

      protected 'cacheControl' => 
        array (size=0)
          empty
  protected 'content' => string '{
  "name":"Steve Jobs 2",
  "email":"s@trp2.com",
  "password":"something123",
}' (length=85)
  protected 'languages' => null
  protected 'charsets' => null
  protected 'encodings' => null

因此我可以在 Request 对象中看到 content，但无论我尝试什么，它始终为 null。所以我的问题是，我究竟该如何访问它？!

谢谢!

Answer 1

您可能想使用 $request->getContent()。