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java - 为 JTable 中的不同单元格添加不同的 JComboBox

转载 作者:行者123 更新时间:2023-12-02 05:32:35 26 4
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假设我有一个代表 Person 的对象。每个人都有一个名字和一系列爱好。

现在,我想为我拥有的人员列表创建一个包含 2 列的表。第一列将显示该人的姓名,第二列将在组合框中显示爱好列表。

问题是,我迭代我的人员列表以填充表。所以我没有办法在一开始就知道“第 1 行将有组合框 X,第 2 行将有组合框 Y 等等”。我只会在运行时知道这些事情。

有什么想法吗?

最佳答案

单元格编辑由CellEditor提供。这基本上意味着每一列都将具有相同的单元格编辑器。有很多方法可以解决这个问题,但让我们保持简单。

假设爱好列表是有限的,并且该列表对于所有人来说都是相同的,那么创建一个基于 JComboBoxCellEditor 并应用将是一件简单的事情放到 table 上

首先查看 Concepts: Editors and RenderersUsing Other Editors

combo box editor

import java.awt.EventQueue;
import java.util.ArrayList;
import java.util.List;
import javax.swing.ComboBoxModel;
import javax.swing.DefaultCellEditor;
import javax.swing.DefaultComboBoxModel;
import javax.swing.JComboBox;
import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
import javax.swing.table.AbstractTableModel;

public class Hobbies {

public static void main(String[] args) {
new Hobbies();
}

public Hobbies() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}

List<Person> people = new ArrayList<>(25);
people.add(new Person("Mellisa"));
people.add(new Person("Annabell"));
people.add(new Person("Margarita"));
people.add(new Person("Steve"));
people.add(new Person("Christel"));

DefaultCellEditor editor = new DefaultCellEditor(new JComboBox(createHobbiesComboBoxModel()));

PersonTableModel model = new PersonTableModel(people);
JTable table = new JTable(model);
table.getColumnModel().getColumn(1).setCellEditor(editor);

JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new JScrollPane(table));
frame.pack();
frame.setLocationByPlatform(true);
frame.setVisible(true);
}
});
}

public ComboBoxModel createHobbiesComboBoxModel() {
String[] hobbies = {"3D Printing",
"A vintage scrapbook",
"Amateur radio[1]",
"Baton twirling",
"Cleaning",
"Computer programming",
"Cooking",
"Coloring",
"Cosplaying",
"Creative writing",
"Crocheting",
"Cryptography",
"Dance",
"Digital arts",
"Drama",
"Drawing",
"Drinking Coffee",
"Eating",
"Electronics",
"Embroidery",
"Foreign language learning",
"Gaming (tabletop games and role-playing games)",
"Gambling",
"Genealogy",
"Homebrewing"};
return new DefaultComboBoxModel(hobbies);
}

public class PersonTableModel extends AbstractTableModel {

private List<Person> people;

public PersonTableModel(List<Person> person) {
people = new ArrayList<>(person);
}

@Override
public int getRowCount() {
return people.size();
}

@Override
public int getColumnCount() {
return 2;
}

@Override
public boolean isCellEditable(int rowIndex, int columnIndex) {
return columnIndex == 1;
}

@Override
public String getColumnName(int columnIndex) {
String value = null;
switch (columnIndex) {
case 0:
value = "Name";
break;
case 1:
value = "Hobby";
break;
}
return value;
}

@Override
public void setValueAt(Object aValue, int rowIndex, int columnIndex) {
if (columnIndex == 1) {
Person person = people.get(rowIndex);
person.setHobby(aValue == null ? null : aValue.toString());
fireTableCellUpdated(rowIndex, columnIndex);
}
}

@Override
public Object getValueAt(int rowIndex, int columnIndex) {
Object value = null;
Person person = people.get(rowIndex);
switch (columnIndex) {
case 0:
value = person.getName();
break;
case 1:
value = person.getHobby();
break;
}
return value;
}

}

public class Person {

private String name;
private String hobby;

public Person(String name) {
this.name = name;
}

public void setHobby(String hobby) {
this.hobby = hobby;
}

public String getName() {
return name;
}

public String getHobby() {
return hobby;
}

}

}

关于java - 为 JTable 中的不同单元格添加不同的 JComboBox,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25377813/

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