java - 比较多个字符串并排序答案

Question

我正在尝试比较 3 个不同的单词，然后对它们进行排序，但是我没有得到正确的答案。一些方向将会有很大的帮助!对 Java 非常陌生，并且已经在这个问题上停留太久了。

到目前为止我正在使用这个:

`// word1, word2, and word3 
   /* If word1 is greater than word2, 
    * and word2 IS greater than word3 and word3 is NOT greater then word1: display word1,     word2, word3 
    */
   result1  =   word1.compareTo(word2);
   result1a =   word1.compareTo(word3);
   result1b =   word2.compareTo(word3);

//display and compare information
       if (result1 > result1a + result1b)  
       JOptionPane.showMessageDialog(null, word1 + word2 + word3);

       else if (result1 < result1a + result1b)
       JOptionPane.showMessageDialog(null, word2 + word3 + word1);

`

Answer 1

String message;
if(word2.compareTo(word1) < 0) { //word2 < word1
    if(word3.compareTo(word1) < 0) { //word3 < word1
        if(word3.compareTo(word2) < 0) { //word3 < word2
            message = word3 + word2 + word1;
        } else { //word2 <= word3
            message = word2 + word3 + word1;
        }
    } else { //word1 <= word3
        message = word2 + word1 + word3;
    }
} else { //word1 <= word2
    if(word3.compareTo(word2) < 0) { //word3 < word2
        if(word3.compareTo(word1) < 0) { //word3 < word1
            message = word3 + word1 + word2;
        } else { //word1 <= word3
            message = word1 + word3 + word2;
        }
    } else { //word2 <= word3
        message = word1 + word2 + word3;
    }
}

这是使用字典顺序/字母顺序。如果您想使用长度来比较单词，则必须将每个 s1.compareTo(s2) 替换为 s1.length() - s2.length() (您如果 s1 大于 s2，则应为正整数。