gpt4 book ai didi

java - 我的应用程序 "find frequency of audio input from microphone"总是崩溃。但为什么?

转载 作者:行者123 更新时间:2023-12-02 05:29:51 28 4
gpt4 key购买 nike

最后你会看到错误信息!!

import java.nio.ByteBuffer;  
import java.nio.ByteOrder;

import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.TargetDataLine;

导入 Math3 以使用 fft。

import org.apache.commons.math3.complex.Complex;  
import org.apache.commons.math3.transform.DftNormalization;
import org.apache.commons.math3.transform.FastFourierTransformer;
import org.apache.commons.math3.transform.TransformType;

public class AudioInput {

TargetDataLine microphone;

final int audioFrames= 8196; //power ^ 2

final float sampleRate= 8000.0f;
final int bitsPerRecord= 16;
final int channels= 1;
final boolean bigEndian = true;
final boolean signed= true;

byte byteData[]; // length=audioFrames * 2
double doubleData[]; // length=audioFrames only reals needed for apache lib.
AudioFormat format;
FastFourierTransformer transformer;

public AudioInput () {

byteData= new byte[audioFrames * 2]; //two bytes per audio frame, 16 bits

//doubleData= new double[audioFrames * 2]; // real & imaginary
doubleData= new double[audioFrames]; // only real for apache

transformer = new FastFourierTransformer(DftNormalization.STANDARD);

System.out.print("Microphone initialization\n");
format = new AudioFormat(sampleRate, bitsPerRecord, channels, signed, bigEndian);
DataLine.Info info = new DataLine.Info(TargetDataLine.class, format); // format is an AudioFormat object

if (!AudioSystem.isLineSupported(info)) {
System.err.print("isLineSupported failed");
System.exit(1);
}

try {
microphone = (TargetDataLine) AudioSystem.getLine(info);
microphone.open(format);
System.out.print("Microphone opened with format: "+format.toString()+"\n");
microphone.start();
}catch(Exception ex){
System.out.println("Microphone failed: "+ex.getMessage());
System.exit(1);
}

}

public int readPcm(){
int numBytesRead=
microphone.read(byteData, 0, byteData.length);
if(numBytesRead!=byteData.length){
System.out.println("Warning: read less bytes than buffer size");
System.exit(1);
}
return numBytesRead;
}


public void byteToDouble(){
ByteBuffer buf= ByteBuffer.wrap(byteData);
buf.order(ByteOrder.BIG_ENDIAN);
int i=0;

while(buf.remaining()>2){
short s = buf.getShort();
doubleData[ i ] = (new Short(s)).doubleValue();
++i;
}
//System.out.println("Parsed "+i+" doubles from "+byteData.length+" bytes");
}


public void findFrequency(){
double frequency;
Complex[] cmplx= transformer.transform(doubleData, TransformType.FORWARD);
double real;
double im;
double mag[] = new double[cmplx.length];

for(int i = 0; i < cmplx.length; i++){
real = cmplx[i].getReal();
im = cmplx[i].getImaginary();
mag[i] = Math.sqrt((real * real) + (im*im));
}

double peak = -1.0;
int index=-1;
for(int i = 0; i < cmplx.length; i++){
if(peak < mag[i]){
index=i;
peak= mag[i];
}
}
frequency = (sampleRate * index) / audioFrames;
System.out.print("Index: "+index+", Frequency: "+frequency+"\n");
}

/* * 打印第一个频率档以了解我们拥有的分辨率 */

    public void printFreqs(){  
for (int i=0; i<audioFrames/4; i++){
System.out.println("bin "+i+", freq: "+(sampleRate*i)/audioFrames);
}
}

public static void main(String[] args) {
AudioInput ai= new AudioInput();
int turns=10000;
while(turns-- > 0){
ai.readPcm();
ai.byteToDouble();
ai.findFrequency();
}


//ai.printFreqs();
}
}

以下是控制台中包含错误消息的内容:

麦克风初始化麦克风打开格式:PCM_SIGNED 8000.0 Hz,16 位,单声道,2 字节/帧,big-endian

Exception in thread "main" org.apache.commons.math3.exception.MathIllegalArgumentException: 8.196 is not a power of 2, consider padding for fix
at org.apache.commons.math3.transform.FastFourierTransformer.transformInPlace(FastFourierTransformer.java:229)
at org.apache.commons.math3.transform.FastFourierTransformer.transform(FastFourierTransformer.java:375)
at AudioInput.findFrequency(AudioInput.java:88)
at AudioInput.main(AudioInput.java:126)

最佳答案

8196 不是 2 的幂。尝试将变量 audioFrames 更改为 final int audioFrames= 8192;。 FFT 算法只能处理大小为 2 的幂的数组(2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, ...)

关于java - 我的应用程序 "find frequency of audio input from microphone"总是崩溃。但为什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25666623/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com