java - 连接4 java水平不被识别

Question

一切正常，但我的水平获胜条件我觉得很奇怪，因为我的垂直工作正常，但我无法解释为什么水平不行，但我的垂直我可以假设你可以将 for 循环切换为行和col ，水平和垂直反之亦然，但它似乎在这里失败了

我尝试过查找一些东西，但到处都在说做我已经做过的事情

public class Connect4 {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    // DON'T MODIFY THE MAIN METHOD UNLESS FOR DEBUGGING
  //MAKE SURE YOU GET RID OF YOUR MODIFICATIONS HERE BEFORE 
SUBMISSION

String[][] board = createEmptyBoard();

Scanner input = new Scanner(System.in);

boolean bl = true;

printPattern(board);

while(bl) {

    int player1 = 1 , player2 = 2 ,  userInput;


   System.out.println("Please drop a RED disk at the column between 
0 and 6:");
    userInput = input.nextInt();
    dropDisk(board, userInput , player1);
    printPattern(board);

   System.out.println("Please drop a YELLOW disk at the column 
between 0 and 6:");
   userInput  = input.nextInt();
   dropDisk(board, userInput , player2);
   printPattern(board);  


    String win = checkWinner(board);

    if(!win.equals(""))
        {
            System.out.println(win + " is the winner!");
            break;
        }
    /*
    Write code to announce  if there is  winner and end the game
    */

     } 
    }
     public static String[][] createEmptyBoard() {
   /* This method prints the first empty pattern for the game
   DON'T MODIFY THIS METHOD
   */
    String[][] f = new String[7][15];
    for (int i =0;i<f.length;i++) {
          for (int j =0;j<f[i].length;j++) {

             if (j% 2 == 0) f[i][j] ="|";
             else f[i][j] = " ";
             if (i==6) f[i][j]= "-";
         }
       }
    return f;

     } // end of createEmptyBoard 


     public static void printPattern(String[][] brd) {

         for (int i = 0; i < 7; i++){

      System.out.println(brd[i][0] + brd[i][1]+ brd[i][2]+ brd[i]
[3]+ brd[i][4]+ brd[i][5]+ brd[i][6]+ brd[i][7]+ brd[i][8]+ brd[i]
[9]+ 

brd[i][10]+ brd[i][11]+ brd[i][12]+ brd[i][13]+ brd[i][14]);


     }

     } // end of printPattern

     public static String dropDisk(String[][] brd, int position, 
int player) {

    if(position < 0 || position > 6){

             return null;

         }

    String disk = player == 1 ? "R" : "Y";

         int col = 2 * position + 1;
         // start looking for a free slot at the very bottom

         int row = 5;

         while (row >= 0 && !brd[row][col].equals(" ")) {

         // move one row up

         row--;

         }

// free slot found, disk can be placed

if (row >= 0) {

    brd[row][col] = disk;

    return disk;

}

return null;

  } // end of dropDisk


   public static String checkWinner(String[][] brd) {      

for(int i = 0; i < 6; i++){

        int count = 0;

        for(int j = 0; j < 14; j++){

            if(brd[i][j].equals("R")){

                count++;

            }
            else {
                count = 0;
            }

            if(count == 4){

                return "R";

            }

        }        

    }

    //Vertical Check for "Y"
    for(int i = 0; i < 6; i++){

        int count = 0;

        for(int j = 0; j < 14; j++){

            if(brd[i][j].equals("Y")){

                count++;

            }

            else{
                count = 0;
            }

            if(count == 4){

                return "Y";

            }
        }        
    }

    // Horizontal Check for "R"
    for(int i = 0; i < 14; i++){

        int count = 0;

        for(int j = 0; j < 6; j++){

            if(brd[j][i].equals("R")){

                count++;

            }

            else {

                count = 0;

            }

            if(count == 4){

                return "R";

            }

        }     

    }

    // Horizontal Check for "Y"
    for(int i = 0; i < 14; i++){

        int count = 0;

        for(int j = 0; j < 6; j++){

            if(brd[j][i].equals("Y")){

                count++;

            }

            else {
                count = 0;
            }

            if(count == 4){

                return "Y";

            }

        }    

    }

    // Check for a diagonal to the bottom and right
    for(int i = 0; i < brd.length-4; i++){

        for(int j = 1; j < brd[i].length-7; j = j + 2){

            if(brd[i][j].equals("R")){

                if(brd[i+1][j+2].equals("R") && brd[i+2]
[j+4].equals("R") && brd[i+3][j+6].equals("R")){

                    return "R";

                }

            }
            else if(brd[i][j].equals("Y")){

                if(brd[i+1][j+2].equals("Y") && brd[i+2]\
[j+4].equals("Y") && brd[i+3][j+6].equals("Y")){

                    return "Y";

                }

            }

        }

    }

    // Check for a diagonal to the bottom and left
    for(int i = 0; i < brd.length-4; i++){

        for(int j = brd[i].length-2; j >= 7; j = j - 2){

            if(brd[i][j].equals("R")){

                if(brd[i+1][j-2].equals("R") && brd[i+2][j-
4].equals("R") && brd[i+3][j-6].equals("R")){

                    return "R";
                }
            }
            else if(brd[i][j].equals("Y")){

                if(brd[i+1][j-2].equals("Y") && brd[i+2][j-
4].equals("Y") && brd[i+3][j-6].equals("Y")){

                    return "Y";

                }
            }
        }
    }

    return "";

}

}

Answer 1

在您的董事会设置中，您有:

 if (j% 2 == 0) f[i][j] ="|";

换句话说，您的列在“R”/“Y”/“”播放位置和“|”之间交替。列标记。

所以你永远不能在水平(或对角线)线上有 4 个“R”或“Y” - 你会有“R”，“|”，“R”，“|”，“R” ，“|”，“R”。

最好删除“|”从你的数组中 - 你不需要存储它们，它只会使你的所有处理变得复杂。只需让数组存储您的棋子，并且仅使用“|”打印时。