c - 声明结构类型，将值插入到该类型的数组中，并打印出数组

Question

在这个程序中，我想定义一个名为 person 的结构，以及一个插入函数，用于将一个元素插入到声明为类型 person 的数组中未使用的空间中。最后，我想将结果作为标准输出打印出来。谁能给我一个提示来纠正任何错误的地方？干杯

错误:

arrays.c:16:22: error: expected ')' before '[' token
arrays.c: In function 'main':
arrays.c:34:5: warning: implicit declaration of function 'insert'
arrays.c:41:5: warning: format '%s' expects type 'char *', but argument 2 has type 'char **'

代码

#include <stdio.h>

/* these arrays are just used to give the parameters to 'insert',
   to create the 'people' array */
char *names[7]= {"Simon", "Suzie", "Alfred", "Chip", "John", "Tim",
          "Harriet"};
int ages[7]= {22, 24, 106, 6, 18, 32, 24};


/* declare your struct for a person here */
typedef struct{
  char name;
  int ages; 
}  person;

static void insert (p[], char *name, int ages) {

  static int nextfreeplace = 0;
  /* put name and age into the next free place in the array parameter here */
  person p[0] = {&name, age};

  /* modify nextfreeplace here */
  nextfreeplace++;

}

int main(int argc, char **argv) {

  /* declare the people array here */
   person p[7];

   //insert the members and age into the unusage array. 
  for (int i=0; i < 7; i++) {
    insert (p[i], &names[i], ages[i]);
    p[i]= p[i+1];

  }

  /* print the people array here*/
  for (int i=0; i < 7; i++) {
    printf("%s is %d years old\n", &names[i], ages[i]);
  }

  return 0;
}

Answer 1

第一个问题是你的struct person。您将名称声明为 char，而它应该是 char*(指针) 或 char[](数组)。。

typedef struct 
{
    char *name; //or char name[100];
    int age;
}
person;

接下来，您的insert function 参数不正确。您不需要一组人员(您可以这样做，但这更简单)，您需要一个指向人员结构的指针，以便您可以对其进行编辑。

static void insert(person *p, char *name, int age)
{
    p->name = name;
    p->age = age;
}

最后，这是填充数组并将其打印出来的方式:

int main()
{
    //names and ages...

    person people[7];

    for (int i = 0; i < 7; i++)
    {
        insert(&people[i], names[i], ages[i]);
    }

    for (int i = 0; i < 7; i++)
    {
        printf("name: %s, age: %i\n", people[i].name, people[i].age);
    }
}

示例:http://ideone.com/dzGWId .