Python在数据框中扩展网络地址

Question

我有一个类似于以下内容的数据框:

df:

    ip          last_active
192.167.0.9     01/02/2012
226.90.2.12     05/06/2013
10.90.2.09      05/06/2014
12.60.2.80     
192.168.2.11-17 05/06/2016

有没有办法扩展 df 中最后一行的 IP 地址？一个完美的解决方案是:

df:

    ip          last_active
192.167.0.9     01/02/2012
226.90.2.12     05/06/2013
10.90.2.09      05/06/2014
12.60.2.80     
192.168.2.11    05/06/2016
192.168.2.12    05/06/2016
192.168.2.13    05/06/2016
192.168.2.14    05/06/2016
192.168.2.15    05/06/2016
192.168.2.16    05/06/2016
192.168.2.17    05/06/2016

感谢任何指导!

Answer 1

您可以应用一个函数来在范围元素中创建 IP 列表，然后如果您有最新的 pandas 版本，请使用 explode()

def ip_splitter(ip):
    if '-' in ip:
        last_octet_range=[int(i) for i in ip.split('.')[3].split('-')]
        new_ips = [i for i in range(last_octet_range[0],last_octet_range[1]+1)]
        expanded_range = ['.'.join(ip.split('.')[:3]+[str(i)]) for i in new_ips]
        return expanded_range
    return ip

df['ip']=df['ip'].apply(ip_splitter)

df

    ip                                                  last_active
0   192.167.0.9                                         01/02/2012
1   226.90.2.12                                         05/06/2013
2   10.90.2.09                                          05/06/2014
3   12.60.2.80                                          None
4   [192.168.2.11, 192.168.2.12, 192.168.2.13, 192...   05/06/2016

df.explode('ip')

    ip              last_active
0   192.167.0.9     01/02/2012
1   226.90.2.12     05/06/2013
2   10.90.2.09      05/06/2014
3   12.60.2.80      None
4   192.168.2.11    05/06/2016
4   192.168.2.12    05/06/2016
4   192.168.2.13    05/06/2016
4   192.168.2.14    05/06/2016
4   192.168.2.15    05/06/2016
4   192.168.2.16    05/06/2016
4   192.168.2.17    05/06/2016