scala - Scala 隐式参数的 Groovy 等价物

Question

是否有一些 Groovy 替代方案来表达如下内容:

def doSomethingWith(implicit i:Int) = println ("Got "+i)
implicit var x = 5

doSomethingWith(6)  // Got 6
doSomethingWith     // Got 5

x = 0
doSomethingWith     // Got 0

更新:在此处查看后续问题:Groovy equivalent for Scala implicit parameters - extended

Answer 1

您可以使用带有默认参数的闭包:

doSomethingWith = { i = value -> println "Got $i" }
value = 5

doSomethingWith(6)  // Got 6
doSomethingWith()   // Got 5

value = 0
doSomethingWith()   // Got 0