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php - 如何在 PHP 上获取 count(*)?

转载 作者:行者123 更新时间:2023-12-02 05:21:54 24 4
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我有以下来自 MySQL 的输出。

Array
(
[0] => stdClass Object
(
[id] => 19
[date] => 2010-10-04 11:00:00
[course] => Yoga
[course_id] => 19
[count(*)] => 2
[capacity] => 20
)

[1] => stdClass Object
(
[id] => 20
[date] => 2010-10-04 13:00:00
[course] => Spin
[course_id] => 20
[count(*)] => 1
[capacity] => 24
)
...
...

我可以获取日期、类(class)等,但我不确定如何使用 PHP 获取计数 (*)。

foreach ($bookingnum as $key => $list){
echo "<tr valign='top'>\n";
echo "<td align='center'>".$list->date."</td>\n";
echo "<td align='center'>".$list->course."</td>\n";
// echo "<td align='center'>".$list->count(*)."</td>\n";
// this is wrong. how to get count(*)??
....
...

最佳答案

将您的基本查询修改为

SELECT COUNT(*) AS `total` ...

那么你可以把它当作

$list->total

关于php - 如何在 PHP 上获取 count(*)?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3931853/

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