java - 如何限制数组中的打印次数？

Question

非常接近让这个程序工作，但我被困住了。我想要它做的只是打印出实际出现的数字，所以如果用户输入:1,2,3,2,6

需要显示

1 - 1 times
2 - 2 times
3 - 1 times
6 - 1 times

我使用相同的输入实际上得到的是这样的:

1 - 1 times
2 - 2 times
3 - 1 times
4 - 0 times 
5 - 0 times
6 - 1 times

我需要删除没有发生的情况。

 import java.util.Arrays; 
 import java.util.Scanner;
 public class CountOccurrences
 {
      public static void main (String [] args)
      {
      Scanner input = new Scanner(System.in);

      //Create Array for numbers
      int numbers[] = new int[100];

      //Prompt user input
      System.out.println("Enter integers between 1 and 100: ");
       //For loop to continue input
       for (int i = 0; i < numbers.length; i++) {
            int next = input.nextInt(); 
               //Breaks loop if 0 is inputted
                if (next==0)
                  {
                     break; 
                       } 
            numbers[i] = next; 
                }

         //Calls on countInts method
       int[] count = countInts(numbers); 
         //Calls on display counts
       displayIntCount(count); 

      }  

     //Counts each instance of a integer
    public static int[] countInts(int[] ints)
    {
        int[] counts = new int[100];

        for(int i = 1; i <=counts.length; i++)
            for(int j=0;j<ints.length;j++)

                if(ints[j] == i)
                    counts[i-1]++;
        return counts;
    }

     //Displays counts of each integer
    public static void displayIntCount(int[] counts)
    {
          for (int i = 0; i < counts.length; i++)
            System.out.println((i+1) +" - " +counts[i] +" Times");
    }
}

Answer 1

只需使用一个简单的 if 语句来检查 counts[i] 是否不为 0，如下所示:

public static void displayIntCount(int[] counts)
{
     for (int i = 0; i < counts.length; i++) {
          if (counts[i] != 0) {
              System.out.println((i+1) +" - " +counts[i] + " Times");
          }
     }
}