java - 查找创建的确切 SOAP 请求和响应 xml

Question

如何找到生成的确切 SOAP 请求和响应。这是我正在使用的示例代码:

@WebService(targetNamespace = "", name = "")
@XmlSeeAlso({ObjectFactory.class})
public interface ServiceSoap {

    @WebMethod(action = "")
    @RequestWrapper(localName = "", targetNamespace = "", className = "")
    @ResponseWrapper(localName = "", targetNamespace = "", className = "")
    @WebResult(name = "", targetNamespace = "")

    public ResponseType sampleRequest(@WebParam(name = "", targetNamespace = "")java.lang.String str);

    }

这是由以下代码片段调用的

ResponseType response = serviceSoap.sampleRequest(str);

我想找到生成的确切 SOAP 请求/响应是什么。

Answer 1

如果您使用 Apache CXF，则可以使用类 LoggingOutInterceptor 和 LoggingInInterceptor:

StringWriter soapMessageWriter=new StringWriter();
LoggingOutInterceptor loi=new LoggingOutInterceptor(new PrintWriter(soapMessageWriter));
loi.setPrettyLogging(true);
ClientProxy.getClient(serviceSoap).getOutInterceptors().add(loi);
LoggingInInterceptor lii=new LoggingInInterceptor(new PrintWriter(soapMessageWriter));
lii.setPrettyLogging(true);
ClientProxy.getClient(serviceSoap).getInInterceptors().add(lii);


//do your stuff

String soapContent=soapMessageWriter.getString();