java - 如何拒绝Java构造函数中的不合格参数？

Question

我遇到一个问题，我正在编写一个Java类，它的承包商需要两个参数，参数是一个图像对象-BufferedImage，我需要检查图像的宽度和高度。

One rule is - imageOne's wight need be the same as imageTwo, if not I want the application to stop and raise message to tell user that the two images are not good(unqualified).

我想应该有一种常规方法可以用 Java 处理我的想法，也许我需要 rasie 异常(exception)？

抱歉，添加我编写的部分代码:

public class Replacer { // This class to merge two images, so it need they have same width.

private BufferedImage smallImage;
private BufferedImage bigImage;

Replacer(BufferedImage smallImage, BufferedImage bigImage) {

    // I want the smallImage and bigImage have same weight        

    this.setSmallImage(smallImage);
    this.setBigImage(bigImage);

    wOfNewScreen = bigImage.getWidth();
    hOfSmallImage = smallImage.getHeight();
    hOfBigImage = bigImage.getHeight();

    if (wOfNewScreen != samllImage.getWidth()) {

        System.out.println("ERROR: The two images don't have same width!!");
    }

}

//... }

有人可以帮忙吗？提前致谢!

芦苇

Answer 1

正确!异常(exception)是最好的选择。

相反，打印错误消息的行只需执行此操作即可。

throw new IllegalArgumentException("Both pictures need to be of same width");