Ansible Lineinfile : Find a key and replace only the value

Question

我有一个 .properties/.conf/.xml/.csv 文件。要求是我需要匹配一个键并仅在该文件中存在该键时才替换该值。

我的 .properties 文件如下所示，

name=newname
surname=newname

下面是我的 key_value.yml 文件

---
properties:
- {  name: name, value: jon}
- { name: surname, value: miller }

下面是我做同样的任务。

---
- name: Find and replace
  lineinfile:
    dest: /tmp/example/example.properties
    regexp: "{{ item.name }}"
    line: "{{ item.value }}"
    inserafter: '{{ item.name }}='
    backrefs: yes
    state: present
  with_items:
    - "{{ properties }}"

但这似乎不起作用。它取代了整条线。请帮忙!

Answer 1

尝试在行中包含 key :

---
- name: Find and replace
  lineinfile:
    dest: /tmp/example/example.properties
    regexp: "{{ item.name }}"
    line: "{{ item.name }}={{ item.value }}"
    backrefs: yes
    state: present
  with_items:
    - "{{ properties }}"