php - 需要总时间中的空闲时间段

Question

有一个音调，音调有自己的开始时间和结束时间(例如从 8:00 AM 到 7:00 PM)。多场比赛已经安排在球场上一段时间了。 (例如，从 8:30AM 到 9:00AM，10:00AM 到 10:30AM)所以现在我要计算的是球场上的可用时间。我的代码在这里:

$pitchStart = '2018-06-11 08:00 AM';
$pitchClose = '2018-06-11 09:00 PM';

$firstGameStart = '2018-06-11 09:30 AM';
$firstGameEnd = '2018-06-11 10:00 AM';

$secondGameStart = '2018-06-11 10:00 AM';
$secondGameEnd = '2018-06-11 10:30 AM';

$thirdGameStart = '2018-06-11 11:00 AM';
$thirdGameEnd = '2018-06-11 11:30 AM';


$Result = [
    [0] => ['freeSlotStart' => '2018-06-11 08:00 AM','freeSlotEnd' => '2018-06-11 09:30 AM'],
    [1] => ['freeSlotStart' => '2018-06-11 10:30 AM','freeSlotEnd' => '2018-06-11 11:00 AM'],
    [2] => ['freeSlotStart' => '2018-06-11 11:30 AM','freeSlotEnd' => '2018-06-11 09:00 PM'],
];

Answer 1

球场是免费的:

1. 在比赛之间。
2. 在 opening time of the pitch 之间和 start of the first game .
3. 在 end of the last game 之间和 closing time of the pitch .

如果您将游戏存储在数组而不是变量中，您可以通过遍历数组来简单地确定上述情况的时间(如果适用)。

---

按照这些思路可能会起作用:

<?php
$pitchOpeningTimes =
    [
        'pitchStart' => '2018-06-11 08:00 AM',
        'pitchClose' => '2018-06-11 09:00 PM'
    ];

$games = [
    [
        'GameStart' => '2018-06-11 09:30 AM',
        'GameEnd' => '2018-06-11 10:00 AM',
    ],
    [
        'GameStart' => '2018-06-11 10:00 AM',
        'GameEnd' => '2018-06-11 10:30 AM',
    ],
    [
        'GameStart' => '2018-06-11 11:00 AM',
        'GameEnd' => '2018-06-11 11:30 AM',
    ]
]; // Assuming these are sorted ascending, if this assumption is wrong, sort it.

function openSlots($openingTimes, $plannedGames)
{
    if (count($plannedGames) == 0) { # No games planned, pitch is free all day.
        return ['freeSlotStart' => $openingTimes['pitchStart'], 'freeSlotEnd' => $openingTimes['pitchClose']];
    }

    $freeslots = []; # We need a result array to push our free slots to.

    // First edge case: pitch might be free between pitchStart and start of the first game
    // if game doesn't start at opening of the pitch.
    if ($plannedGames[0]['GameStart'] !== $openingTimes['pitchStart']) {
        $freeslots[] = [
            'freeSlotStart' => $openingTimes['pitchStart'],
            'freeSlotEnd' => $plannedGames[0]['GameStart']
        ];
    }

    // Loop over the games to check for open slots between games.
    for ($g = 0; $g < count($plannedGames) - 1; $g++) {
        if ($plannedGames[$g]['GameEnd'] !== $plannedGames[$g + 1]['GameStart']) {
            // echo $g;
            $freeslots[] = [
                'freeSlotStart' => $plannedGames[$g]['GameEnd'],
                'freeSlotEnd' => $plannedGames[$g + 1]['GameStart']
            ];
        }
    }

    // Second edge case: pitch might be free between pitchEnd and end of the last game
    // If game doesn't end at the time the pitch closes.
    $lastGame = end($plannedGames);
    if ($lastGame['GameEnd'] !== $openingTimes['pitchClose']) {
        $freeslots[] = [
            'freeSlotStart' => $lastGame['GameEnd'],
            'freeSlotEnd' => $openingTimes['pitchClose']
        ];
    }

    return $freeslots;
}

var_dump(openSlots($pitchOpeningTimes, $games));

注意:

1. 将日期时间作为字符串进行比较(可能)不是最佳做法。
2. 上面的代码不是很优雅。
3. 我还没有测试此代码以输出所需的结果。至少它应该是一个正确方向的好提示。

---

编辑:

在您的您的代码无法正常工作评论之后，我花了大约 10 秒的时间:

1. 添加echo $g;到 for 循环。
2. 注意 for 循环没有执行。
3. 请注意，增量和条件被调换了。

从某种意义上说，我的代码是有效的——正如我所说的——它只是试图将您推向正确的方向。我强烈认为，花在快速修复上的时间不应该是我的，而是你的。不管怎样，长篇大论够了，我已经改变了:for ($g = 0; $g++; $g < count($plannedGames) - 1)至 for ($g = 0; $g < count($plannedGames) - 1; $g++) .希望对您有所帮助。