java - "CopyOnWriteArrayList"和 "ConcurrentHashMap"可以序列化吗？

Question

我有一个使用 RMI 的类传送。但我不确定这些线程安全对象是否可以序列化。有人尝试过吗？

更新skaffman说是的，但是我序列化失败了。

这是我传送的类(class)。

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package net.shisoft.beans;

import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.CopyOnWriteArrayList;

/**
 *
 * @author Shisoft
 */
public class WhatzNewList {

    ConcurrentHashMap<String, CopyOnWriteArrayList<WhatzNewEntry>> WhatzNewTable = new ConcurrentHashMap<String, CopyOnWriteArrayList<WhatzNewEntry>>();
    String user;

    public ConcurrentHashMap<String, CopyOnWriteArrayList<WhatzNewEntry>> getWhatzNewTable() {
        return WhatzNewTable;
    }

    public void setWhatzNewTable(ConcurrentHashMap<String, CopyOnWriteArrayList<WhatzNewEntry>> WhatzNewTable) {
        this.WhatzNewTable = WhatzNewTable;
    }

    public String getUser() {
        return user;
    }

    public void setUser(String usere) {
        this.user = usere;
    }

    public WhatzNewList(String user) {
        this.user = user;
    }
}

这是类WhatzNewEntry

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package net.shisoft.beans;

import java.util.Date;

/**
 *
 * @author Shisoft
 */
public class WhatzNewEntry {
    String Title;
    String context;
    String contact;
    Date Time;

    public Date getTime() {
        return Time;
    }

    public void setTime(Date Time) {
        this.Time = Time;
    }

    public String getTitle() {
        return Title;
    }

    public void setTitle(String Title) {
        this.Title = Title;
    }

    public String getContact() {
        return contact;
    }

    public void setContact(String contact) {
        this.contact = contact;
    }

    public String getContext() {
        return context;
    }

    public void setContext(String context) {
        this.context = context;
    }

}

也许斯卡夫曼是对的，但是这里有什么问题吗？

Answer 1

它们都实现了java.io.Serialized。所以是的，它们可以被序列化。

当然，它们的内容是否可以序列化完全是另一个问题。