java - 结尾逻辑错误

Question

我即将完成本周到期的一个项目。它是一个按升序获取数组的交集和差集的程序。就方法而言，一切都正常，但我试图在用户响应之间添加换行符，但我必须在某个地方删除了某些内容，并且无法找到该部分的日志。它应该只是重复 do while 循环中的内容，但是当我第二次再次执行时，它看起来像是将我要输入 int 的数字集相乘。我知道这一定是一个简单的逻辑错误，但此时我的头很痛。

这是我到目前为止得到的:

import java.util.Scanner;
public class settest {

    public static Scanner kbd = new Scanner(System.in);

    /*
     * This method will retrieve "size" number of unique
     * integers from keyboard and placed into an array set. 
     */
    public static void getData(int [] set, int size){

        boolean isUnique=false;
        int input; int count=0;

        while(count < size){
            input = kbd.nextInt();
            for(int i=0; i < size; i++) 
            {
                if (input == set[i]) 
                {
                    isUnique = true;
                }   
            }

            if (!isUnique) 
            {
                set[count] = input;
                count++;
            }
            isUnique = false;
        }

    }

    /*
     * This method will calculate the intersection of two sets of arrays.
     * It needs to receive two sets of arrays, their size, and a holding
     * array as parameters from the main program.
     * When finished the method will return the numbers that are in common
     * in both sets (resultSize) 
     */
    public static int intersection(int [] setA, int sizeA , int [] setB, 
            int sizeB, int [] resultSet){

        int resultSize=0;
        for(int x=0; x<sizeA; x++)
        {
            for(int y=0; y<sizeB; y++)
            {
                if(setA[x]==setB[y])
                {
                    resultSet[resultSize]=setA[x];
                    resultSize++;
                }
            }
        }

        return resultSize;
    }

    /*
     * Calculates the difference (A-B) of the two array sets. 
     * It will received the set [], size of correct array and in 
     * ascending order as parameters.
     * Returns the correct array size for the received resultSet[]
     */
    public static int difference(int [] setA, int sizeA , int [] setB, 
            int sizeB, int [] resultSet){

        int resultSize=0; boolean sameVal=false;

        for(int x=0; x<sizeA; x++ ){
            for(int y=0; y<sizeB; y++){
                if(setA[x]==setB[y]){
                    sameVal=true;
                }
            }
            if(!sameVal){
                resultSet[resultSize]=setA[x];
                resultSize++;
            }
            sameVal=false;
        }
        return resultSize;
    }

    /*
     * Method will sort the numbers in set[] array into ascending order. 
     */
    public static void sort(int [] set, int size){

        for(int x=0; x< size-1; x++)
        {
            for(int y=x+1; y<size; y++)
            {   
                if(set[x] > set[y])
                {
                    int temp = set[x];
                    set[x] = set[y];
                    set[y] = temp;
                }
            }     
        }
    }

    public static final int MAXSIZE = 20;

    public static void main(String[] args) {
        int [] setA = new int[MAXSIZE];
        int [] setB = new int[MAXSIZE];
        int [] resultSet = new int[MAXSIZE];
        int sizeA=0, sizeB=0;int resultSize=0;
        String repeat;

        do{
            System.out.println("ENTER 2 SETS OF NUMBERS.\n");
            System.out.println("HOW MANY NUMBERS IN YOUR FIRST SET?");
            sizeA=kbd.nextInt();
            for(int i=0; i<sizeA; i++){

                if (sizeA>MAXSIZE){
                    System.out.println("\nERROR: SET SIZE LIMIT EXCEEDED."
                            + "ENTER A DIFFERENT AMOUNT. \n");
                    sizeA = kbd.nextInt();
                }

            }
            System.out.println("\nENTER THE FIRST SET OF NUMBERS");

            getData(setA, sizeA);
            sort(setA,sizeA);


            System.out.println("\nHOW MANY NUMBERS IN YOUR SECOND SET?");
            sizeB=kbd.nextInt();
            for(int i=0; i<sizeB; i++){

                if (sizeB>MAXSIZE){
                    System.out.println("\nERROR: SET SIZE LIMIT EXCEEDED.  \n"
                            + "ENTER A DIFFERENT AMOUNT.\n ");
                    sizeB = kbd.nextInt();
                }

            }
            System.out.println("\nENTER THE SECOND SET OF NUMBERS");

            getData(setB, sizeB);
            sort(setB, sizeB);

            System.out.println("\nINTERSECTION:");
            resultSize=intersection(setA,sizeA,setB,sizeB, resultSet);
            for(int i=0; i<resultSize; i++){
                System.out.print(resultSet[i] + " ");
            }

            System.out.println("\n\nDIFFERENCE OF A-B:");
            resultSize=difference(setA,sizeA,setB,sizeB, resultSet);
            for(int i=0; i<resultSize; i++){
                System.out.print(resultSet[i]+" ");
            }
            System.out.println("\n\nDIFFERENCE OF B-A:");
            resultSize=difference(setB,sizeB,setA,sizeA, resultSet);
            for(int i=0; i<resultSize; i++){
                System.out.print(resultSet[i]+" ");
            }
            System.out.println("\n\nDO YOU WANT TO CONTINUE?");

            repeat= kbd.next().toLowerCase();

        } while(repeat.equals("y"));

    }

}

任何帮助将不胜感激。

ENTER 2 SETS OF NUMBERS.

您的第一组中有多少个数字？3

输入第一组数字432

您的第二组中有多少号码？2

输入第二组数字56

交叉点:

A-B 的差异:2 3 4

B-A 的区别:5 6

您想继续吗？是输入 2 组数字。

您的第一组中有多少个数字？1

输入第一组数字6

您的第二组中有多少号码？6

输入第二组数字3541097

交叉点:

A-B 的差异:6

B-A 的区别:1 3 4 5 7 9

您想继续吗？8再见

在循环的第二次循环中，用户数量以某种方式增加到广告 1 或几个的位置

Answer 1

我相信下面的代码会对您有所帮助。您可以将初始化数组部分移至 while 循环中，以便可以根据用户输入初始化数组的大小。

public static void main(String[] args) {
    int sizeA=0, sizeB=0;int resultSize=0;
    String repeat;

    do{        
        System.out.println("ENTER 2 SETS OF NUMBERS.\n");
        System.out.println("HOW MANY NUMBERS IN YOUR FIRST SET?");
        sizeA=kbd.nextInt();

        int [] setA = new int[sizeA ]; //Initializing Array of size that user inputs.

        for(int i=0; i<sizeA; i++){

            if (sizeA>MAXSIZE){
                System.out.println("\nERROR: SET SIZE LIMIT EXCEEDED."
                        + "ENTER A DIFFERENT AMOUNT. \n");
                sizeA = kbd.nextInt();
            }

        }
        System.out.println("\nENTER THE FIRST SET OF NUMBERS");

        getData(setA, sizeA);
        sort(setA,sizeA);


        System.out.println("\nHOW MANY NUMBERS IN YOUR SECOND SET?");
        sizeB=kbd.nextInt();

        int [] setB = new int[sizeB]; //Initializing Array of size that user inputs.

        for(int i=0; i<sizeB; i++){

            if (sizeB>MAXSIZE){
                System.out.println("\nERROR: SET SIZE LIMIT EXCEEDED.  \n"
                        + "ENTER A DIFFERENT AMOUNT.\n ");
                sizeB = kbd.nextInt();
            }

        }
        System.out.println("\nENTER THE SECOND SET OF NUMBERS");

        getData(setB, sizeB);
        sort(setB, sizeB);

        /* Initializing the result array with Largest among sizeA and sizeB*/
        resultSize = sizeA;
        if(sizeB > sizeA)
        {
             resultSize = sizeB;
        }
        int [] resultSet = new int[resultSize];

        System.out.println("\nINTERSECTION:");
        resultSize=intersection(setA,sizeA,setB,sizeB, resultSet);
        for(int i=0; i<resultSize; i++){
            System.out.print(resultSet[i] + " ");
        }

        System.out.println("\n\nDIFFERENCE OF A-B:");
        resultSize=difference(setA,sizeA,setB,sizeB, resultSet);
        for(int i=0; i<resultSize; i++){
            System.out.print(resultSet[i]+" ");
        }
        System.out.println("\n\nDIFFERENCE OF B-A:");
        resultSize=difference(setB,sizeB,setA,sizeA, resultSet);
        for(int i=0; i<resultSize; i++){
            System.out.print(resultSet[i]+" ");
        }
        System.out.println("\n\nDO YOU WANT TO CONTINUE?");

        repeat= kbd.next().toLowerCase();

    } while(repeat.equals("y"));