datetime - SQL Server 2008 将 int 转换为 dd :hh:mm

Question

如何将代表分钟的 int 值(即:1800)转换为如下所示的值:dd:hh:mm(天:小时:分钟)。

所以1800应该转换成1:06:00(1天6小时0分钟)。

在存储过程中我有这个:

SELECT 
    Record_ID, Project_ID, Ticket_ID, WO_Type, DC, Title, Device_Quantity, 
    Total/1440 as Total,  
    ((Total - Elapsed) - DATEDIFF(mi, Record_Time, getdate())) as FinalTimeLeft, 
    Completed 
FROM Record

我如何将转换实现到 SP 中？以上 FinalTimeLeft=1800

Answer 1

这个例子如何 - 它计算小时、分钟和秒，但应该很容易修改天、小时和分钟:

SELECT 
  CAST(mins / 3600 AS VARCHAR) + ':' + 
  RIGHT('0' + CAST((mins % 3600) / 60  AS VARCHAR), 2) + ':' +
  RIGHT('0' + CAST(mins % 60 AS VARCHAR), 2)
FROM 
  (SELECT 1800 AS mins) a

编辑:包括您的存储过程和我针对天、小时和分钟修改的代码:

SELECT 
  *
  ,CAST(FinalTimeLeft / 1440 AS VARCHAR) + ':' +
     RIGHT('0' + CAST((FinalTimeLeft / 60) % 24 AS VARCHAR), 2) + ':' +
     RIGHT('0' + CAST(FinalTimeLeft % 60 AS VARCHAR), 2) AS duration
FROM ( 
SELECT 
  Record_ID
  ,Project_ID
  ,Ticket_ID
  ,WO_Type
  ,DC
  ,Title
  ,Device_Quantity
  ,Total/1440 as Total
  ,((Total-Elapsed)-DATEDIFF(mi,Record_Time,getdate())) as FinalTimeLeft
  ,Completed
FROM record) a