java - 循环逻辑中的漏洞

Question

我正在尝试一个异常处理程序来计算以厘米为单位的高度。

import java.util.*;
class Ex{
private static double height(int feet, int inches) throws Exception{
        if(feet < 0 || inches < 0)
            throw new Exception("Please enter positive values only.");
        return (feet * 30.48) + (inches * 2.54);
    }

 public static void main(String args[]){
 Scanner scanner=new Scanner(System.in);
 boolean continueLoop = true;

 do{
     try
     {
         System.out.println("Enter height in feet:");
         int feet=scanner.nextInt();
         System.out.println("and in inches:");
         int inches = scanner.nextInt();
         double result = height(feet,inches);
         System.out.println("Result:"+result+" cm");
         continueLoop = false;
     }
     catch(InputMismatchException e){
         System.out.println("You must enter integers. Please try again.");
     }
     catch(Exception e){
         System.out.println(e.getMessage());
     }
 }while(continueLoop);
}
}

当发生InputMismatchException时，程序进入无限循环。我这里的逻辑有什么问题吗？我应该做什么改变？

Answer 1

您应该将 scanner.nextLine() 添加到您的 catch block 中，以便消耗当前行的其余部分，以便 nextInt 可以尝试读取新输入从下一行开始。

 do{
     try
     {
         System.out.println("Enter height in feet:");
         int feet=scanner.nextInt();
         System.out.println("and in inches:");
         int inches = scanner.nextInt();
         double result = height(feet,inches);
         System.out.println("Result:"+result+" cm");
         continueLoop = false;
     }
     catch(InputMismatchException e){
         System.out.println("You must enter integers. Please try again.");
         scanner.nextLine();
     }
     catch(Exception e){
         System.out.println(e.getMessage());
         scanner.nextLine();
     }
 }while(continueLoop);