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java - 比较两个字符串数组在不同的地方给出不同的输出

转载 作者:行者123 更新时间:2023-12-02 05:07:18 24 4
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我有一个方法,可以正常工作并给出所需的结果。这是它的代码:

public class arraycomparison {

public static void main(String args[]) {
try {

Scanner sc1 = new Scanner(new FileInputStream("/Users/esna786/File1.txt"));
Scanner sc2 = new Scanner(new FileInputStream("/Users/esna786/File2.txt"));
List<String> File1Content = new ArrayList<String>();
List<String> File2Content = new ArrayList<String>();
List<String> commonWords = new ArrayList<String>();

//Getting the contents of File1
while (sc1.hasNext()) {
File1Content.add(sc1.next());
}
String arr1[] = File1Content.toArray(new String[File1Content.size()]);

//Getting the contents of File1
while (sc2.hasNext()) {
File2Content.add(sc2.next());
}
String arr2[] = File2Content.toArray(new String[File2Content.size()]);

int count = 0;

for (int i = 0; i < arr1.length; i++) {
for (int j = 0; j < arr2.length; j++) {
if (arr1[i].equals(arr2[j])) {
commonWords.add(arr1[i]);
count++;
}
}
}

String[] comWords = commonWords.toArray(new String[commonWords.size()]);

System.out.println("Total Number of Common Words are: "+comWords.length);
for (int i = 0; i < comWords.length; i++) {
System.out.println(i + 1 + ": " + comWords[i]);
}


} catch (Exception e) {
e.printStackTrace();
}
}

}

它的输出是,

Total Number of Common Words are: 7
1: apple
2: ball
3: cat
4: duck
5: elephant
6: fan
7: goat
BUILD SUCCESSFUL (total time: 0 seconds)

当我运行下面的程序代码时使用相同的文件几乎与上面相同:

//Counting the number of matched words
public int getCommonWords(File File1, File File2) throws IOException {
try {

Scanner sc1 = new Scanner(new FileInputStream(File1));
Scanner sc2 = new Scanner(new FileInputStream(File1));
List<String> File1Content = new ArrayList<String>();
List<String> File2Content = new ArrayList<String>();
List<String> commonWords = new ArrayList<String>();

//Getting the contents of File1
while (sc1.hasNext()) {
File1Content.add(sc1.next());
}
String arr1[] = File1Content.toArray(new String[File1Content.size()]);

//Getting the contents of File1
while (sc2.hasNext()) {
File2Content.add(sc2.next());
}
String arr2[] = File2Content.toArray(new String[File2Content.size()]);

int count = 0;

for (int i = 0; i < arr1.length; i++) {
for (int j = 0; j < arr2.length; j++) {
if (arr1[i].equals(arr2[j])) {
commonWords.add(arr1[i]);
count++;
}
}
}

String[] comWords = commonWords.toArray(new String[commonWords.size()]);

System.out.println("Total Number of Common Words are: " + comWords.length);
for (int i = 0; i < comWords.length; i++) {
System.out.println(i + 1 + ": " + comWords[i]);
}

} catch (Exception e) {
e.printStackTrace();
}
return 0;
}

它在输出区域显示以下内容:

run:
Total words of File1.txt are: 11
Total Number of Common Words are: 11
1: apple
2: ball
3: cat
4: duck
5: elephant
6: fan
7: goat
8: a
9: b
10: c
11: d

还显示不匹配的单词,为什么会这样呢?请帮忙。

最佳答案

这是因为在您的第二个源中,您正在读取如下所示的同一文件:

Scanner sc1 = new Scanner(new FileInputStream(File1));
Scanner sc2 = new Scanner(new FileInputStream(File1));//change this to File2

关于java - 比较两个字符串数组在不同的地方给出不同的输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27674786/

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