vba - 使用 .Cells 时出现无效或不合格的引用错误

Question

我正在尝试创建Excel模板(数据量因情况而异)，它看起来像这样:

在每个偶数行中都是“客户”，我想在每个奇数行中放入“Ledger”。基本上，它应该将“Ledger”放入每个奇数行，直到 C 列中有数据。我有以下代码:

'========================================================================
' INSERTING LEDGERS for every odd row (below Customer)
'========================================================================

Sub Ledgers()

    Dim rng As Range
    Dim r As Range
    Dim LastRow As Long

    LastRow = .Cells(.Rows.Count, "C").End(xlUp).Row
    Set rng = .Range("C5:C" & LastRow)

    For i = 1 To rng.Rows.Count
        Set r = rng.Cells(i, -2)
        If i Mod 2 = 1 Then
            r.Value = "Ledger"
        End If

    Next i

End Sub

但它给了我一个错误消息无效或不合格的引用。您能告诉我哪里有错误吗？

非常感谢!

Answer 1

如果命令以 . 开头(例如 .Cells)，则它期望位于 with 语句中，例如 ...

With Worksheets("MySheetName")
    LastRow = .Cells(.Rows.Count, "C").End(xlUp).Row
    Set rng = .Range("C5:C" & LastRow)
End With

因此您需要指定单元格所在的工作表的名称。

并不是说在模块顶部使用 Option Explicit 来强制声明每个变量是一个好主意(您错过了声明 i As Long ) )。

您的代码可以简化为...

Option Explicit 

Public Sub Ledgers()
    Dim LastRow As Long
    Dim i As Long

    With Worksheets("MySheetName") 
        LastRow = .Cells(.Rows.Count, "C").End(xlUp).Row

        'make sure i starts with a odd number
        'here we start at row 5 and loop to the last row
        'step 2 makes it overstep the even numbers if you start with an odd i
        'so there is no need to proof for even/odd
        For i = 5 To LastRow Step 2 
            .Cells(i, "A") = "Ledger" 'In column A
            '^ this references the worksheet of the with-statement because it starts with a `.`
        Next i
    End With
End Sub