java - java中返回文件未找到异常时尝试继续程序

Question

当 url 没有图像时，我能够读取 csv 中的行并从 url 下载图像，它显示在程序中间未找到文件异常，我想继续该程序而不终止。

public static void main(String[] args) throws IOException {
    InputStream inputStream = null;
    OutputStream outputStream = null;
    try {
        BufferedReader br = new BufferedReader(new FileReader("D:\\imgdwnld\\file.csv"));
        String line = br.readLine(); 
        while ((line = br.readLine()) !=null){
            URL url = new URL(line);
            inputStream = url.openStream();
            outputStream = new FileOutputStream("D:\\imgdwnld\\" +
                line.substring(line.lastIndexOf("/")));
            byte[] buffer = new byte[2048];
            int length;
            while ((length = inputStream.read(buffer)) != -1) {
                outputStream.write(buffer, 0, length);
            }
        }
    } catch (MalformedURLException e) {
        System.out.println("MalformedURLException :- " + e.getMessage());
    } catch (FileNotFoundException e) {
        System.out.println("FileNotFoundException :- " + e.getMessage());
    } catch (IOException e) {
        System.out.println("IOException :- " + e.getMessage());
    } finally {
        try {
            inputStream.close();
            outputStream.close();
        } catch (IOException e) {
            System.out.println("Finally IOException :- " + e.getMessage());
        }
    }
}

Answer 1

这是您的代码的相关概要:

try {
  ...
  while ((line = br.readLine()) !=null) {
      ... process each CSV line ...
  }
} catch (IOException e) {
  ... handle it ...
}

在捕获异常的地方，您已经脱离了主循环。更改代码以具有以下轮廓:

while ((line = br.readLine()) !=null) {
  try {
    ... process one CSV line ...
  } catch (IOException e) {
    ... handle it, the loop will proceed with the next line
  }
}