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c - 使用 MPI_Gather 接收数据结构的正确方法

转载 作者:行者123 更新时间:2023-12-02 05:02:52 26 4
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我尝试使用 MPI_Gather 发送以下数据结构:

struct set {
int nbits;
char bits[];
};

问题是我无法收集上述结构的所有项目,只能收集第一项。其余项目根本没有意义。

这是一个测试用例:

#include <stdio.h>
#include <stdlib.h>

#include "mpi.h"

#define SIZE 10

struct set {
int nbits;
char bits[];
};

int main(int argc, char *argv[]) {
int np, rank, i;
struct set *subsets, *single;
void *buf;

MPI_Init(&argc,&argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &np);

single = malloc(sizeof(struct set) + SIZE);

if(rank == 0) {
subsets = malloc((sizeof(struct set) + SIZE) * np);
}

buf = &subsets[0];

MPI_Datatype set_type, oldtypes[2];
int blockcounts[2];
MPI_Aint offsets[2];
MPI_Aint addr[3];

MPI_Get_address(single, &addr[0]);
MPI_Get_address(&single->nbits, &addr[1]);
MPI_Get_address(&single->bits, &addr[2]);

offsets[0] = addr[1] - addr[0];
oldtypes[0] = MPI_INT;
blockcounts[0] = 1;

offsets[1] = addr[2] - addr[0];
oldtypes[1] = MPI_CHAR;
blockcounts[1] = SIZE;

MPI_Type_create_struct(2, blockcounts, offsets, oldtypes, &set_type);
MPI_Type_commit(&set_type);

single->nbits = 2;

for(i=0; i<single->nbits; i++)
single->bits[i] = 'A' + rank;

MPI_Gather(single, 1, set_type, buf, 1, set_type, 0, MPI_COMM_WORLD);

if(rank == 0) {
void *ptr;
struct set *fs;
int size;

MPI_Type_size(set_type, &size);

ptr = buf;

for(i=0; i<np; i++) {
size_t j;

fs = ptr;
printf("from rank %d: bits => %p nbits => %d\n", i, fs->bits, fs->nbits);

for(j=0; j<2; j++)
printf("from rank %d: buf[%d] = %#x\n",
i, j, fs->bits[j]);
ptr += size;
}
}

MPI_Type_free(&set_type);

MPI_Finalize();
}

如有任何帮助,我们将不胜感激。

最佳答案

问题不在于MPI,而在于结构和 MPI 类型的指针算法。

你有

        void *ptr;
struct set *fs;
int size;

MPI_Type_size(set_type, &size);

ptr = buf;

for(i=0; i<np; i++) {
size_t j;

fs = ptr;
printf("from rank %d: bits => %p nbits => %d\n", i, fs->bits, fs->nbits);

for(j=0; j<2; j++)
printf("from rank %d: buf[%d] = %#x\n",
i, j, fs->bits[j]);
ptr += size;
}
}

但是MPI_Type_size实际上给出了类型中的数据量;如果有填充(可能会在这里使字符数组位于单词边界上),这与 sizeof 不同。如果你想在这里使用 MPI 函数,如果你将那个函数调用切换到 MPI_Type_extent ,它实际上告诉您该类型跨越的整个范围,您的代码为我运行...但仍然存在问题。

如果您看一下 sizeof(struct set)+SIZEMPI_Type_extent() 之间的区别,您会发现它们并不相同;这个:

#define SIZE 10
struct set {
int nbits
char nbits[]
}

...

malloc(sizeof(struct set)+SIZE);

不一样

struct set {
int nbits
char nbits[SIZE]
}

malloc(sizeof(struct set));

因为padding等,这意味着subsets的大小不对,调用MPI_Gather时内存错误。

你可以通过几种不同的方式解决这个问题,但最简单的(也是最短的行数)是定义结构,其中数组已经确定大小,然后使用数组索引而不是指针算法:

#include <stdio.h>
#include <stdlib.h>

#include "mpi.h"

#define SIZE 10

struct set {
int nbits;
char bits[SIZE];
};

int main(int argc, char *argv[]) {
int np, rank, i;
struct set *subsets, *single;

MPI_Init(&argc,&argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &np);

single = malloc(sizeof(struct set));

if(rank == 0) {
subsets = malloc(sizeof(struct set) * np);
}

MPI_Datatype set_type, oldtypes[2];
int blockcounts[2];
MPI_Aint offsets[2];
MPI_Aint addr[3];

MPI_Get_address(single, &addr[0]);
MPI_Get_address(&single->nbits, &addr[1]);
MPI_Get_address(&single->bits, &addr[2]);

offsets[0] = addr[1] - addr[0];
oldtypes[0] = MPI_INT;
blockcounts[0] = 1;

offsets[1] = addr[2] - addr[0];
oldtypes[1] = MPI_CHAR;
blockcounts[1] = SIZE;

MPI_Type_create_struct(2, blockcounts, offsets, oldtypes, &set_type);
MPI_Type_commit(&set_type);

single->nbits = 2;

for(i=0; i<single->nbits; i++)
single->bits[i] = 'A' + rank;

MPI_Gather(single, 1, set_type, &(subsets[0]), 1, set_type, 0, MPI_COMM_WORLD);

if(rank == 0) {
for(i=0; i<np; i++) {
struct set *fs = &(subsets[i]);
printf("from rank %d: bits => %p nbits => %d\n", i, fs->bits, fs->nbits);

for(int j=0; j<2; j++)
printf("from rank %d: buf[%d] = %#x\n",
i, j, fs->bits[j]);
}
}

MPI_Type_free(&set_type);

MPI_Finalize();
}

已更新以添加如果您不能这样做,只需更改缓冲区分配的大小以将数据收集到:

#include <stdio.h>
#include <stdlib.h>
#include "mpi.h"

#define SIZE 10

struct set {
int nbits;
char bits[];
};

int main(int argc, char *argv[]) {
int np, rank, i;
struct set *single;
void *buf;
ptrdiff_t extent;

MPI_Init(&argc,&argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &np);

single = malloc(sizeof(struct set) + SIZE);

MPI_Datatype set_type, oldtypes[2];
int blockcounts[2];
MPI_Aint offsets[2];
MPI_Aint addr[3];

MPI_Get_address(single, &addr[0]);
MPI_Get_address(&single->nbits, &addr[1]);
MPI_Get_address(&single->bits, &addr[2]);

offsets[0] = addr[1] - addr[0];
oldtypes[0] = MPI_INT;
blockcounts[0] = 1;

offsets[1] = addr[2] - addr[0];
oldtypes[1] = MPI_CHAR;
blockcounts[1] = SIZE;

MPI_Type_create_struct(2, blockcounts, offsets, oldtypes, &set_type);
MPI_Type_commit(&set_type);

MPI_Type_extent(set_type, &extent);
buf = malloc((int)extent * np);

single->nbits = 2;

for(i=0; i<single->nbits; i++)
single->bits[i] = 'A' + rank;

MPI_Gather(single, 1, set_type, buf, 1, set_type, 0, MPI_COMM_WORLD);

if(rank == 0) {
struct set *fs = buf;
for(i=0; i<np; i++) {
printf("from rank %d: bits => %p nbits => %d\n", i, fs->bits, fs->nbits);

for(int j=0; j<2; j++)
printf("from rank %d: buf[%d] = %#x\n",
i, j, fs->bits[j]);

fs = (struct set *)((char *)fs + extent);
}
}

MPI_Type_free(&set_type);

MPI_Finalize();
}

关于c - 使用 MPI_Gather 接收数据结构的正确方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14673886/

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