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java - 井字棋游戏。循环困难和扫描仪问题

转载 作者:行者123 更新时间:2023-12-02 04:59:54 25 4
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我正在为类制作井字游戏程序。我已经在程序中构建了表格和所有内容,但仍然存在一些问题。这是我的完整代码。

import java.util.Scanner;

public class TicTacToe {

//These two variables are for placing the X's and O's in the TicTacToe table.
static int row;
static int col;

//This array is for the TicTacToe table.
static char[][] table = new char[3][3];

//This is for ending the while statement that controls the game
static boolean continuePlaying = true;
static boolean exitProgram = false;

//This is for returning true when the user inputs a valid combination of numbers
static boolean validMove = true;

//This is for returning false when the user inputs an invalid combination of numbers
static boolean invalidMove = false;

//These will store the names for player 1 and 2
static String p1;
static String p2;

//This variable will change every turn to either p1 or p2 depending on who's turn it is. (This is a bad idea at the moment)
static String activePlayer;

//This variable is to count the number of games played
static int gamesCounter = 0;

//These two variables are to keep track of the wins each player has
static int p1Wins = 0;
static int p2Wins = 0;

static void clearTable(){
for(int i = 0; i < table.length; i++){
table[i][i] = ' ';
}
}

//This is my displayTable() method. This will show the table and the X's or O's each player has played
static void displayTable(){
System.out.println(" 0 1 2");
System.out.println("0[" + table[0][0] +"][" + table[0][1] +"][" + table[0][2] +"]");
System.out.println("1[" + table[1][0] +"][" + table[1][1] +"][" + table[1][2] +"]");
System.out.println("2[" + table[2][0] +"][" + table[2][1] +"][" + table[2][2] +"]");
}

//This is my move(int row,int col) method. This will record the moves each player takes and insert X's or O's depending on which player
static boolean move(int row,int col) {
//This if statement will return false if the user enters in coordinates outside the 3x3 zone.
if (row > 2 || row < 0) {
System.out.println("Invalid move."); return false;
}
//This if statement checks if the array already has an X or O in the chosen space. If the array is already filled it will return false.
else if (table[row][col] == 'X' || table[row][col] == 'O') {
System.out.println("Not available."); return false;
}
else return true;
}

//This is my checkRow method. It checks for 3 X's or O's in a row. If there are 3 in a row it will return true, if not, it returns false.
static boolean checkRow(int row){
if((table[row][0] & table[row][1] & table[row][2]) == 'X') return true;
if((table[row][0] & table[row][1] & table[row][2]) == 'O') return true;
else return false;
}

//This is my checkCol method. It checks for 3 X's or O's in a row. If there are 3 in a row it will return true, if not, it returns false.
static boolean checkCol(int col){
if((table[0][col] & table[1][col] & table[2][col]) == 'X') return true;
if((table[0][col] & table[1][col] & table[2][col]) == 'O') return true;
else return false;
}

//This is my checkDiagonal method. It checks for 3 X's or O's in a row. If there are 3 in a row it will return true, if not, it returns false.
static boolean checkDiagonal(){
if((table[0][0] & table[1][1] & table[2][2]) == 'X') return true;
if((table[2][0] & table[1][1] & table[0][2]) == 'X') return true;
if((table[0][0] & table[1][1] & table[2][2]) == 'O') return true;
if((table[2][0] & table[1][1] & table[0][2]) == 'O') return true;
else return false;
}

//This is my checkWinner method. It runs all the other checks to see if anyone won.
//If there is a winner the method returns true. If there is no winner yet, the method returns false.
static boolean checkWinner(){
if(checkRow(0) == true) return true;
if(checkRow(1) == true) return true;
if(checkRow(2) == true) return true;
if(checkCol(0) == true) return true;
if(checkCol(1) == true) return true;
if(checkCol(2) == true) return true;
if(checkDiagonal() == true) return true;
else return false;
}

public static void main(String[] args) {
//The Scanner for asking each player's names
Scanner s = new Scanner(System.in);

//The beginning structure of the TicTacToe program
System.out.println("TicTextToe");
System.out.print("Name of player 1: ");
p1 = s.nextLine();

//This line of code is just to check if it's taking Player 1's name correctly
//System.out.println(p1);

//Asks for Player 2's name
System.out.print("Name of player 2: ");
p2 = s.nextLine();

//This line of code is just to check if it's taking Player 2's name correctly
//System.out.println(p2);

//Printing move(row, col) to see why it's printing unusually
//System.out.print(move(row, col));


//The TicTacToe table set up, coordinates provided around the squares
//The displayTable() method will be used to display the table here. There will be no X's or O's in the table this first time.
while (continuePlaying == true) {
displayTable();
System.out.print("Player " + p1 + ":");
row = s.nextInt();
col = s.nextInt();
move(row, col);

//This will display the table again and ask for proper coordinates.
while(move(row, col) == false) {
displayTable();
System.out.println("Player " + p1 + ":");
row = s.nextInt();
col = s.nextInt();
move(row,col);
}

//This inputs the X into the table if move(row, col) returns true.
if(move(row, col) == true) {
table[row][col] = 'X';
}
//This will check if p1 just won the game or if the game needs to continue
checkRow(0);
//System.out.println(checkRow(0)); //This prints out if row 0 is true or false
checkRow(1);
//System.out.println(checkRow(1)); //This prints out if row 1 is true or false
checkRow(2);
//System.out.println(checkRow(2)); //This prints out if row 2 is true or false
checkCol(0);
//System.out.println(checkCol(0)); //This prints out if column 0 is true or false
checkCol(1);
//System.out.println(checkCol(1)); //This prints out if column 1 is true or false
checkCol(2);
//System.out.println(checkCol(2)); //This prints out if column 2 is true or false
checkDiagonal();
//System.out.println(checkDiagonal()); //This prints out true or false depending on the diagonals
checkWinner();
//System.out.println(checkWinner()); //This prints out if checkWinner is true or false. If it's true the while loop should end

if(checkWinner() == true){
displayTable();
System.out.println("Player " + p1 + " wins!");
gamesCounter++;
p1Wins++;
clearTable();
System.out.println(p1 + " " + p1Wins + "/" + gamesCounter);
System.out.println(p2 + " " + p2Wins + "/" + gamesCounter);
System.out.println("Another game? Yes/No :");
if(s.next() == "Yes") {
break;
}
if(s.next() == "No") {
continuePlaying = false;
System.out.println("Statistitcs:");
System.out.println(p1 + p1Wins + "/" + gamesCounter);
System.out.println(p2 + p2Wins + "/" + gamesCounter);
break;
}
}

displayTable();
System.out.print("Player " + p2 + ":");
row = s.nextInt();
col = s.nextInt();
move(row, col);

//This will display the table again and ask for proper coordinates.
while(move(row, col) == false) {
displayTable();
System.out.println("Player " + p2 + ":");
row = s.nextInt();
col = s.nextInt();
move(row,col);
}

//This inputs the O into the table if move(row, col) returns true.
if(move(row, col) == true) {
table[row][col] = 'O';
}
//This will check if p2 just won the game or if the game needs to continue
checkRow(0);
//System.out.println(checkRow(0)); //This prints out if row 0 is true or false
checkRow(1);
//System.out.println(checkRow(1)); //This prints out if row 1 is true or false
checkRow(2);
//System.out.println(checkRow(2)); //This prints out if row 2 is true or false
checkCol(0);
//System.out.println(checkCol(0)); //This prints out if column 0 is true or false
checkCol(1);
//System.out.println(checkCol(1)); //This prints out if column 1 is true or false
checkCol(2);
//System.out.println(checkCol(2)); //This prints out if column 2 is true or false
checkDiagonal();
//System.out.println(checkDiagonal()); //This prints out true or false depending on the diagonals
checkWinner();
//System.out.println(checkWinner()); //This prints out if checkWinner is true or false. If it's true the while loop should end

if(checkWinner() == true){
displayTable();
System.out.println("Player " + p2 + " wins!");
gamesCounter++;
p2Wins++;
System.out.println(p1 + " " + p1Wins + "/" + gamesCounter);
System.out.println(p2 + " " + p2Wins + "/" + gamesCounter);
System.out.println("Another game? Yes/No :");
if(s.next() == "Yes") {
break;
}
if(s.next() == "No") {
continuePlaying = false;
System.out.println("Statistitcs:");
System.out.println(p1 + p1Wins + "/" + gamesCounter);
System.out.println(p2 + p2Wins + "/" + gamesCounter);
break;
}

}

}
{
} while (exitProgram == false);
}
}

今天我要问大家的问题是。当我在程序中完成一个游戏时,它询问我是否想玩另一个游戏。我会输入"is"。什么也不会发生。我必须输入"is"两次才能转到另一个游戏,然后当我的“clearTable();”时方法启动后,它仅替换我程序中的 X,而不替换 O。

有人可以向我解释为什么它不会从我的程序中删除 O 和 x 吗?无论如何,我的方法对我来说非常有意义。

static void clearTable(){
for(int i = 0; i < table.length; i++){
table[i][i] = ' ';
}
}

它将循环直到所有内容都包含“”。但我不确定为什么它现在排除 O。

我担心的另一个问题是,当我完成游戏并输入“否”后,我的程序就会退出。我必须输入“否”两次,然后它只会再次显示我的表格,该表格也不会被清除。这不应该是发生的事情。我的程序应该打印玩家的统计数据,然后退出。有什么想法吗?

最佳答案

据我了解,table是一个二维数组,如果你只做一个for循环并使用table.length();,它不会遍历整个数组。.您的 clearTable 函数会遍历 table[0][0]table[1][1]table[2][ 2] 仅当它应该遍历整个数组时。您应该创建另一个内部 for 循环并使用 table[0].length ,它将返回数组中第二个维度的大小。

static void clearTable(){
for(int i = 0; i < table.length; i++)
for(int j=0; j< table[0].length; j++)
table[i][j] = ' ';
}

希望它能起作用。

至于双"is"和“否”,这是因为您在 if 中调用函数 s.next() 并在回答第一个之后造成的一,它会再次调用s.next()函数。相反,将答案保存在字符串中并像这样进行比较:

string ans = s.next();
if(ans.equals("Yes"))
break;
else if(ans.equals("No")) {
continuePlaying = false;
System.out.println("Statistitcs:");
System.out.println(p1 + p1Wins + "/" + gamesCounter);
System.out.println(p2 + p2Wins + "/" + gamesCounter);
break;
}

关于java - 井字棋游戏。循环困难和扫描仪问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28384204/

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