php - undefined variable 代码点火器

Question

我的 View 有这个错误，我找不到问题出在哪里

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: errors

Filename: views/register_user.php

Line Number: 5

查看:

<?php if($errors){ ?>
<div style="background:red,color:white;">
<?=$errors?>
</div>
<? } ?>

这里是 Controller

function register(){
    if($_POST){
        $config=array(
            array(
                'field'=>'username',
                'label'=>'Username',
                'rules'=>'trim|required|min_length[3]|is_unique[users.username]'
                ),
            array(
                'field'=>'password',
                'label'=>'Password',
                'rules'=>'trim|required|min_length[5]|max_length[15]'
                ),
            array(
                'field'=>'password2',
                'label'=>'Password Confirmed',
                'rules'=>'trim|required|min_length[5]|matches[password]'
                ),
            array(
                'field'=>'user_type',
                'label'=>'User Type',
                'rules'=>'required'
                ),
            array(
                'field'=>'email',
                'label'=>'Email',
                'rules'=>'trim|required|is_unique[users.email]|valid_email'
                )
            );
        $this->load->library('form_validation');
        $this->form_validation->set_rules($config);
        if($this->form_validation->run() == FALSE){
            $data['errors']=validation_errors();
        } else {
        $data=array(
            'username'=>$_POST['username'],
            'password'=>$_POST['password'],
            'user_type'=>$_POST['user_type']
            );
        $this->load->model('user');
        $userid=$this->user->create_user($data);
        $this->session->set_userdata('userID',$userid);
        $this->session->set_userdata('user_type',$_POST['user_type']);
        redirect(base_url().'posts');
    }
}
    $this->load->helper('form');
    $this->load->view('header');
    $this->load->view('register_user');
    $this->load->view('footer');
}

我开始使用 Codeigniter，但找不到问题...

Answer 1

问题是在某些情况下$errors未创建变量。使用 if(isset($errors) && $errors))

实际上在 View 中您只需要 <?php echo validation_errors(); ?> , 无需将其分配给变量

看看http://ellislab.com/codeigniter/user-guide/libraries/form_validation.html有关如何显示错误的更多信息