sql - SQL Server 2008 中的数据透视表

Question

请帮助我解决 SQL Server PIVOT 表中的问题。我得到如下输出。现在我想要在每个日期行下的单独列中分配挂起和编码挂起的总数。

select ScanDate, filestatus, COUNT(filestatus) as filecount from ScanLog 
where FileSource = 'ebridge'
group by filestatus, ScanDate

scandate        filestatus      filecount
2013-08-01  Allocation Pending  8
2013-08-01  Coding Pending      1
2013-08-02  Allocation Pending  4
2013-08-02  Coding Pending      1
2013-08-03  Allocation Pending  4
2013-08-04  Allocation Pending  18
2013-08-04  Coding Pending      3
2013-08-05  Allocation Pending  6

我使用了以下代码但出现错误，因为“scandate”不是有效字段。请指导我。

select [scandate] from ScanLog 
pivot (count(scandate) 
for filestatus in ([allocation pending],[coding pending])) as A
where FileSource = 'ebridge'

Answer 1

试试这个 -

DECLARE @temp TABLE (
      ScanDate DATETIME
    , FileSource VARCHAR(10)    
    , FileStatus VARCHAR(30)
    , FileCount INT

)

INSERT INTO @temp
VALUES 
    ('2013-08-01', 'ebridge', 'Allocation Pending', 8),
    ('2013-08-01', 'ebridge', 'Coding Pending', 1),
    ('2013-08-02', 'ebridge', 'Allocation Pending', 4),
    ('2013-08-02', 'ebridge', 'Coding Pending', 1),
    ('2013-08-03', 'ebridge', 'Allocation Pending', 4),
    ('2013-08-04', 'ebridge', 'Allocation Pending', 18),
    ('2013-08-04', 'ebridge', 'Coding Pending', 3),
    ('2013-08-05', 'ebridge', 'Allocation Pending', 6)

SELECT *
FROM (
    SELECT scandate, filestatus
    FROM @temp
    WHERE FileSource = 'ebridge'
) t
PIVOT (
    COUNT(scandate)
    FOR filestatus IN ([Allocation Pending], [Coding Pending])
) a