java - 缺少方法主体，或声明抽象

Question

我收到此错误消息:

Exception in thread "main" java.lang.RuntimeException: Uncompilable source code - Erroneous sym type: Pet.saySomething at PetTest.main(PetTest.java:18) Java Result: 1

这是我所拥有的:对于Speak类，

public class Speak {
   public void saySomething();
}

这是我在 PetTest 类中的内容:

 import java.util.ArrayList;

 public class PetTest {

     public static void main(String[] args)
     {
         ArrayList<Pet> myPets = new ArrayList<Pet>();

         myPets.add(new Parrot("Boss"));
         myPets.add(new Cat("Oreo"));
         myPets.add(new Dog("Riley"));

         for (Pet p: myPets)
         {
             p.saySomething();
             System.out.println(p);
         }
     }
 }

我没有发布与该程序相关的其他 5 门类(class)。我知道 Speak 类中需要修复一些问题，但我被困住了。在 Speak 类中，在 public void saySomething(); 行中，它表示缺少方法主体，或声明抽象。

编辑:以下是其他类:

 public abstract class Pet {

     String name;

     public Pet(String name){
         this.name = name;
     }
 }

 public class Parrot extends Bird {

     public Parrot (String name)
     {
         super(name);
     }

     @Override
     public void saySomething()
     {
         System.out.println("Pauly want a craker?");
     }

     @Override
     public String toString()
     {
         return "Hello, I'm " + name + " the parrot.";
     }

 }


 public class Dog extends Pet {

     public Dog (String name)
     {
         super(name);
     }

     @Override
     public void saySomething()
     {
         System.out.println("Ruff, ruff!");
     }

     @Override
     public String toString()
     {
         return "Hello, I'm " + name + " the dog.";
     }
 }


 public class Cat extends Pet {

     public Cat(String name)
     {
         super(name);
     }

     @Override
     public void saySomething()
     {
    System.out.println("Meow.");
     }

     @Override
     public String toString()
     {
         return "Hello, I'm " + name + " the cat.";
     }
 }

 public class Bird extends Pet {

     public Bird(String name)
     {
         super(name);
     }

     public void saySomething(){}

 }

Answer 1

您有以下发言选项，请选择:

第一

public abstract class Speak{

   public abstract void saySomething();

}

第二

public class Speak{

   public void saySomething(){

   }
}

第三

public interface Speak{

   public void saySomething();
}

编辑:首先，您没有在任何地方使用 Speak 类。其次，请在Pet类中添加以下方法:

 public abstract void saySomething();