java - 将 List 转换为 Collection 以进行 JUnit 参数化测试

Question

我想使用外部数据执行 JUnit 参数化测试。我有一个对象列表，只需要知道如何将其转换为对象数组的集合。我看到下面的堆栈溢出问题，但我想添加从我的方法读取的文件中的数据。

Parameterized JUnit tests with non-primitive parameters?

工作代码:类似这样:

@RunWith(Parameterized.class)
public class sampletest {

  private BranchMailChildSample branch;

  public sampletest(BranchMailChildSample branch)
  {
    this.branch = branch;
  }

  @Parameters
  public static Collection<Object[]> data()
  {
    String excel = "C:\\Resources\\TestData\\ExcelSheets\\BranchMail\\branchmail_TestData.xlsx";
    ExcelMarshallerTool tool = new ExcelMarshallerTool(excel);
    List<BranchMailChildSample> items = tool.unmarshallExcel(BranchMailChildSample.class);

   //RIGHT HERE I NEED HELP: Convert list to Collection<Object[]>

    //return items as Collection of object arrays 
  }

  @Test
  public void test()
  {
    System.out.println(branch.toString());
  }
}

Answer 1

您不必转换列表。

@RunWith(Parameterized.class)
public class SampleTest {

  @Parameters(name = "{0}")
  public static List<BranchMailChildSample> data() {
    String excel = "C:\\Resources\\TestData\\ExcelSheets\\BranchMail\\branchmail_TestData.xlsx";
    ExcelMarshallerTool tool = new ExcelMarshallerTool(excel);
    return tool.unmarshallExcel(BranchMailChildSample.class);
  }

  @Parameter(0)
  public BranchMailChildSample branch;

  @Test
  public void test() {
    System.out.println(branch.toString());
  }
}

我使用了字段注入(inject)，因为它比构造函数注入(inject)需要更少的代码。将名称设置为测试对象会打印更有用的输出。请查看documentation of the Parameterized runner .

如果您不喜欢公共(public)字段，可以使用构造函数注入(inject)。

@RunWith(Parameterized.class)
public class SampleTest {

  @Parameters(name = "{0}")
  public static List<BranchMailChildSample> data() {
    String excel = "C:\\Resources\\TestData\\ExcelSheets\\BranchMail\\branchmail_TestData.xlsx";
    ExcelMarshallerTool tool = new ExcelMarshallerTool(excel);
    return tool.unmarshallExcel(BranchMailChildSample.class);
  }

  private final BranchMailChildSample branch;

  public SampleTest(BranchMailChildSample branch) {
    this.branch = branch;
  }

  @Test
  public void test() {
    System.out.println(branch.toString());
  }
}