python - 是否存在运算符(operator)错误，因为执行后它说不明确错误。我在做什么错误？

Question

elder_data.head()
    Sex      Name       Fund    Elder Rating    Caretaker Rating
0   Female  A'A NAYHIA  56154           3               3
1   Male    AADHAV      31118           3               4
2   Female  AADHYA      23523           3               2
3   Male    AADIT       13202           2               2
4   Male    AADITH      39505           2               4


 if elder_data['Elder Rating'] >=3 | elder_data['Caretaker Rating'] >=3:
    elder_data["Status"]="Approved"
else:
    elder_data["Status"]="Not Approved"
---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-31-646b023be552> in <module>
----> 1 if elder_data['Elder Rating'] >=3 | elder_data['Caretaker Rating'] >=3:
      2     elder_data["Status"]="Approved"
      3 else:
      4     elder_data["Status"]="Not Approved"

~\Anaconda3\lib\site-packages\pandas\core\generic.py in __nonzero__(self)
   1476         raise ValueError("The truth value of a {0} is ambiguous. "
   1477                          "Use a.empty, a.bool(), a.item(), a.any() or a.all()."
-> 1478                          .format(self.__class__.__name__))
   1479 
   1480     __bool__ = __nonzero__

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

** 我想创建一个新的“状态”列，如果长者评级和看护者评级大于 3，则状态将获得批准

但是我收到一个错误。如何纠正？**

Answer 1

第一个问题是在链接条件中缺少()，因为使用了运算符优先级和设置新值 numpy.where :

elder_data["Status"] = np.where((elder_data['Elder Rating'] >=3) | 
                                (elder_data['Caretaker Rating'] >=3),
                               'Approved',
                               'Not Approved')