java - 声称不相等的值，即使它们是相等的

Question

我正在制作一个简单的乐透游戏，但是当我输入一些数字并将骰子设置为只有 1(100% 获胜机会)时，我仍然得到失败的结果。另外我怎样才能让厄运声明只打印一次？我知道你可以创建一个 boolean 值等，但是有更简单的方法吗？

import java.util.Random;
import java.util.Scanner;

public class Main {

public static void main(String[] args) {
    int num = 0;
    int randnum = 0;
    Random gen = new Random();
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter desired numbers to be drawn");
    int print = scan.nextInt();
    System.out.println("Enter desired numbers on dice");
    int dice = scan.nextInt();
    System.out.println("Enter your lucky numbers");
    int[] numbers = new int[print];
    for(int i=0; i<print;i++){
        numbers[i] = scan.nextInt();
    }
    for(int counter=1; counter<=print;counter++){
        randnum = 1+gen.nextInt(dice);
        System.out.println(randnum + " ");
        System.out.println();
        if (randnum == num){
            System.out.println("Winner winner chicken dinner!");
        } else
            System.out.println("Bad luck!");
        }
    }
}

Answer 1

问题很简单。您没有将 randnum 与正确的变量进行比较。您要做的是将您的条件替换为:

       if (randnum == numbers[counter - 1]){
            System.out.println("Winner winner chicken dinner!");
        } else
            System.out.println("Bad luck!");
        }