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java - 一对一多列外键的断列映射

转载 作者:行者123 更新时间:2023-12-02 04:36:30 25 4
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我有两个实体 RoomNightBookingCorporateDetails,其中 BookingCorporateDetails 在两列(booking_idroom_night_booking_id)。

BookingCorporateDetails 是可选的,但 RoomNight 是必需的。我正在尝试在 BookingCorporateDetails 表上创建一个外键连接 -

AbstractJpaEntity.java

@MappedSuperclass
@SuppressWarnings("serial")
public abstract class AbstractJpaEntity implements Serializable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
protected Long id;

@Column(name = "created_at")
@Temporal(TemporalType.TIMESTAMP)
protected Date createdAt;

@Column(name = "created_by", length = 32, nullable = true)
protected String createdBy;

@Column(name = "updated_at")
@Temporal(TemporalType.TIMESTAMP)
protected Date updatedAt;

@Column(name = "updated_by", length = 32, nullable = true)
protected String updatedBy;

@Column(name = "is_published", columnDefinition = "tinyint(1) default 1")
protected boolean isPublished;

@Column(name = "is_deleted", columnDefinition = "tinyint(1) default 0")
protected boolean isDeleted;

// Getters and Setters
}

AbstractBookingEntity.java

@MappedSuperclass
public abstract class AbstractBookingEntity extends AbstractJpaEntity {

private static final long serialVersionUID = 6980195228404112444L;

@Column(name = "booking_id", nullable = false)
protected String bookingId;

@Column(name = "room_night_booking_id", nullable = false)
protected String roomNightBookingId;

public String getBookingId() {
return bookingId;
}

public void setBookingId(String bookingId) {
this.bookingId = bookingId;
}

public String getRoomNightBookingId() {
return roomNightBookingId;
}

public void setRoomNightBookingId(String roomNightBookingId) {
this.roomNightBookingId = roomNightBookingId;
}
}

BookingCorporateDetailsEntity.java

@Entity(name = "booking_corporate_details")
@Table(name = "booking_corporate_details", uniqueConstraints = { @UniqueConstraint(name = "key_bcd_order_sub_order", columnNames = { "booking_id", "room_night_booking_id" }) })
public class BookingCorporateDetailsEntity extends AbstractBookingEntity {

private static final long serialVersionUID = -5577224607005257364L;

@Column(name = "btc_company")
private String billToCompany;

@Column(name = "cr_company_name", nullable = false)
private String companyName;

@Column(name = "cr_manager_name")
private String managerName;

@Column(name = "cr_manager_email")
private String managerEmail;

@Column(name = "cr_manager_phone")
private String managerPhone;

@OneToOne(optional = true, cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumns({
@JoinColumn(name = "booking_id", referencedColumnName = "booking_id", insertable = false, updatable = false),
@JoinColumn(name = "room_night_booking_id", referencedColumnName = "room_night_booking_id", insertable = false, updatable = false)
})
private RoomNightEntity roomNightEntity;

public RoomNightEntity getRoomNightEntity() {
return roomNightEntity;
}

public void setRoomNightEntity(RoomNightEntity roomNightEntity) {
this.roomNightEntity = roomNightEntity;
}

// Getters And Setters
}

RoomNightEntity.java

@Entity(name = "room_night")
@Table(name = "room_night", uniqueConstraints = { @UniqueConstraint(name = "key_rm_order_sub_order", columnNames = { "booking_id", "room_night_booking_id" }) })
public class RoomNightEntity extends AbstractBookingEntity {

private static final long serialVersionUID = 7661960864475909694L;

@Column(name = "ota_booking_id", nullable = false)
private String otaBookingId;

@Column(name = "property_id", nullable = false)
private Long propertyId;

@Column(name = "room_type_id", nullable = false)
private Integer roomTypeId;

@Column(name = "booking_status", nullable = false)
private Integer bookingStatus;

@Column(name = "occupancy", nullable = false)
private Integer occupancy;

@Column(name = "user_id", nullable = false)
private Long userId;

@Column(name = "payment_mode", nullable = false)
private String paymentMode;

@Column(name = "stay_date")
@Temporal(TemporalType.DATE)
private Date stayDate;

@OneToOne(cascade = CascadeType.ALL, mappedBy = "roomNightEntity", fetch = FetchType.LAZY)
private BookingCorporateDetailsEntity bookingCorporateDetailsEntity;

// Getters and Setters
}

当我执行代码时,出现以下异常 -

java.lang.IllegalStateException: Failed to load ApplicationContext
at org.springframework.test.context.TestContext.getApplicationContext(TestContext.java:201)
at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.injectDependencies(DependencyInjectionTestExecutionListener.java:109)
at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.prepareTestInstance(DependencyInjectionTestExecutionListener.java:75)
at org.springframework.test.context.TestContextManager.prepareTestInstance(TestContextManager.java:255)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.createTest(SpringJUnit4ClassRunner.java:111)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.invokeTestMethod(SpringJUnit4ClassRunner.java:148)
at org.junit.internal.runners.JUnit4ClassRunner.runMethods(JUnit4ClassRunner.java:51)
at org.junit.internal.runners.JUnit4ClassRunner$1.run(JUnit4ClassRunner.java:44)
at org.junit.internal.runners.ClassRoadie.runUnprotected(ClassRoadie.java:27)
at org.junit.internal.runners.ClassRoadie.runProtected(ClassRoadie.java:37)
at org.junit.internal.runners.JUnit4ClassRunner.run(JUnit4ClassRunner.java:42)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:97)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:459)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:675)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:382)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:192)
Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'bookingEntityManagerFactory' defined in class path resource [hibernateJPAConfig.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1578)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:545)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:482)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:306)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197)
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1076)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:851)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:541)
at org.springframework.test.context.support.AbstractGenericContextLoader.loadContext(AbstractGenericContextLoader.java:84)
at org.springframework.test.context.support.AbstractGenericContextLoader.loadContext(AbstractGenericContextLoader.java:42)
at org.springframework.test.context.TestContext.loadApplicationContext(TestContext.java:173)
at org.springframework.test.context.TestContext.getApplicationContext(TestContext.java:197)
... 17 more
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.persistenceException(EntityManagerFactoryBuilderImpl.java:954)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:884)
at org.springframework.orm.jpa.vendor.SpringHibernateJpaPersistenceProvider.createContainerEntityManagerFactory(SpringHibernateJpaPersistenceProvider.java:60)
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:340)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:319)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1637)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1574)
... 30 more
Caused by: org.hibernate.MappingException: broken column mapping for: bookingCorporateDetailsEntity.roomNightEntity of: com.casa.fabbookingbase.entity.RoomNightEntity
at org.hibernate.persister.entity.AbstractPropertyMapping.initPropertyPaths(AbstractPropertyMapping.java:165)
at org.hibernate.persister.entity.AbstractPropertyMapping.initIdentifierPropertyPaths(AbstractPropertyMapping.java:253)
at org.hibernate.persister.entity.AbstractPropertyMapping.initPropertyPaths(AbstractPropertyMapping.java:219)
at org.hibernate.persister.entity.AbstractEntityPersister.initOrdinaryPropertyPaths(AbstractEntityPersister.java:2218)
at org.hibernate.persister.entity.AbstractEntityPersister.initPropertyPaths(AbstractEntityPersister.java:2265)
at org.hibernate.persister.entity.AbstractEntityPersister.postConstruct(AbstractEntityPersister.java:3814)
at org.hibernate.persister.entity.SingleTableEntityPersister.<init>(SingleTableEntityPersister.java:437)
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
at java.lang.reflect.Constructor.newInstance(Constructor.java:422)
at org.hibernate.persister.internal.PersisterFactoryImpl.createEntityPersister(PersisterFactoryImpl.java:96)
at org.hibernate.persister.internal.PersisterFactoryImpl.createEntityPersister(PersisterFactoryImpl.java:77)
at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:344)
at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:465)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:881)
... 35 more

PS:我已经在这里看到了多个示例,但即使尝试了这些解决方案也无法解决问题。

最佳答案

我做了一些测试,它与两个连接列一起工作的唯一方法是从 RoomNightEntity 实体中删除 mappedBy

你最终得到了一种没有父子关系的双向映射:BookingCorporateDetailsEntity

@OneToOne(optional = true, cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumns({
@JoinColumn(name = "booking_id", referencedColumnName = "booking_id", insertable = false, updatable = false),
@JoinColumn(name = "room_night_booking_id", referencedColumnName = "room_night_booking_id", insertable = false, updatable = false)
})
private RoomNightEntity roomNightEntity;

RoomNightEntity

@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@JoinColumns({
@JoinColumn(name = "booking_id", referencedColumnName = "booking_id", insertable = false, updatable = false),
@JoinColumn(name = "room_night_booking_id", referencedColumnName = "room_night_booking_id", insertable = false, updatable = false)
})
private BookingCorporateDetailsEntity bookingCorporateDetailsEntity;

关于java - 一对一多列外键的断列映射,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42152266/

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