objective-c - stringByReplacingOccurrencesOfString 循环？

Question

NSString *qwer2 = [qwer1 stringByReplacingOccurrencesOfString:@"count '0','" withString:@""];

NSString *qwer4 = [qwer2 stringByReplacingOccurrencesOfString:@"count '1','" withString:@""];

NSString *qwer = [qwer4 stringByReplacingOccurrencesOfString:@"count '2','" withString:@""];

如何用任何数字替换字符串？

count '0' , count '1' , count '2'

count 'any numbers'

我已经尝试过循环:

for (int i =0; i<100; i++) 

NSString *qwer = [qwer4 stringByReplacingOccurrencesOfString:@"count 'i','"withString:@""];

Answer 1

NSString *replaced = [string stringByReplacingOccurrencesOfString:@"count '\\d+','"
                           withString:@""
                              options:NSRegularExpressionSearch
                                range:NSMakeRange(0, string.length)];

应该可以解决问题。 "\d+"是匹配一个或多个数字的正则表达式模式。