java - JAX-B 编码问题

Question

我必须使用 JAX-B 进行编码。我有Customer类，Person类(class) Customer有List<Person> personList作为属性。我已经采取了

@XmlRootElement
public class Customer  {

private List<Person> personList;

@XmlElement
public List<Person> getPersonList() {
    return personList;
}

我收到 O/P <customer><personList>person details</personList>但我想要里面的人员详细信息 </person></dependents></customer>

Answer 1

您可以像这样使用@XmlElementWrapper

Customer.java

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "customer")
public class Customer  {

    private List<Person> personList;

    @XmlElementWrapper(name = "personList")
    @XmlElement(name="person")
    public List<Person> getPersonList() {
        return personList;
    }
}

Person.java

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "person")
public class Person {

    private String name;

    @XmlElement(name = "name")
    public String getName() {
        return name;
    }
}

之后您的输出应类似于以下 xml

<customer>
    <personList>
        <person>
            <name>Person 1</name>
        </person>
        <person>
            <name>Person 2</name>
        </person>
    <personList>
</customer>