java - 是否可以合并这两个 do 循环

Question

我尝试将两个循环合并为一个 do 循环，但每次我输入无效值时，它都不会提示我错误消息并要求再次输入该值。相反，它只是转到下一个提示语句。

do {
    try {
        dependents = Integer.parseInt(JOptionPane.showInputDialog("number of dependents:"));
    }
    catch (NumberFormatException e) {
        dependents = MIN_DEPENDENTS - 1;
    }
    if (dependents < MIN_DEPENDENTS || dependents > MAX_DEPENDENTS) {
        JOptionPane.showMessageDialog(null, "Number of dependents must be between 0 and 9.");
    }
} while (dependents < MIN_DEPENDENTS || dependents > MAX_DEPENDENTS);

do {
    try {
        income = Double.parseDouble(JOptionPane.showInputDialog("amount of income:"));
    }
    catch (NumberFormatException e) {
        income = MIN_INCOME - 1;
    }
    if (income < MIN_INCOME || income > MAX_INCOME) {
        JOptionPane.showMessageDialog(null, "income must be between $0 and $999,999.");
    }
} while (income < MIN_INCOME || income > MAX_INCOME);

Answer 1

不，但您可以创建某种 GetInput 函数并传入 min、max、promptText 和 errorText。这将避免您重复代码。

dependents = getInput(MIN_DEPENDENTS, MAX_DEPENDENTS,"number of dependents:","Number of dependents must be between 0 and 9.")
income = getInput(MIN_INCOME,MAX_INCOME,"amount of income:","income must be between $0 and $999,999.")

private double getInput(double min, double max, String promptText, String errorText) {
   double result = 0.0;
   do {
         try {
            result = Double.parseDouble(JOptionPane.showInputDialog(promptText));
         }
         catch (NumberFormatException e) {
            result = min - 1;
         }

         if (result < min || result > max) {
            JOptionPane.showMessageDialog(null, errorText);
         }
   } while (result < min || result > max);

   return result;
}