java :loop user inputs individually

Question

我有一个程序，它告诉用户输入三个int并将每个整数转换为字符串。 即 1 = 1 ； ...等等。这里的问题是为每个用户输入定义int。我怎样才能只用一个输入来获取它并循环它以获取另一个输入，考虑到单独的输入，这样我们就可以在下面的每个短语中单独使用它。

public static void main(String[] args) {

    String[] i = { "zero" , "one" , "two" , "three" , "four" , 
                    "five", "six", "seven" , "eight" , "nine" , "ten" };

    Scanner in = new Scanner(System.in);

    System.out.println("I have ..... Networking books, ..... Database books, and ..... Programming books. ");

    String text = "" , text1 = "", text2 = "" ;    
    // loop i/p and using it in every phrase seperatellty 

    for (int a = 1; a <= 1; a++) {
        int word = in.nextInt();
        int word1 = in.nextInt();
        int word2 = in.nextInt();

        text = i[word];
        text1 = i[word1]; 
        text2 = i[word2]; 
    }

    System.out.println("I have " + text + " Networking books, "
                                        + text1 + "  Database books, and " 
                                        + text2 +" Programming books. ");

}} 

Answer 1

也许这就是你想要做的

注意:

您错过了输入号码的范围检查。如果您尝试访问索引大于 10 的数组 i，这将抛出 ArrayIndexOutOfBoundException

import java.util.*;
class UserInputReader {

    private static final int EXPECTED_NUM_COUNT = 3;

    public static void main(String[] args) {
        String [] i = { "zero" , "one" , "two" , "three" , "four" , 
                    "five", "six", "seven" , "eight" , "nine" , "ten" };

        Scanner in = new Scanner (System.in);   
        String[] words = new String[EXPECTED_NUM_COUNT];

        int numCount = 0;
        while(numCount < 3) {
            System.out.println("Enter the number");
            int num = in.nextInt();
            if (num >= 0 && num <= 10) {
                words[numCount] = i[num];
                numCount++;
            } else {
                System.out.println("Enter no is invalid. Try again entering a number between 0 - 10");
            }
        }

        System.out.println("Entered nums " + Arrays.toString(words));

    }
}