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xml - 修改 Groovy 中现有的 xml 文件

转载 作者:行者123 更新时间:2023-12-02 04:28:12 27 4
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我有一个 pom.xml 文件,例如:

<?xml version="1.0" encoding="utf-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0">
<modelVersion>4.0.0</modelVersion>

<groupId>com.test.plugins</groupId>
<artifactId>testplugin</artifactId>
<packaging>grails-plugin</packaging>
<version>1.0</version>

<name>testplugin</name>
<description>testplugin</description>

<dependencies>
<dependency>
<groupId>org.grails</groupId>
<artifactId>grails-plugin-async</artifactId>
<version>${grails.version}</version>
</dependency>
</dependencies>

<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<configuration>
<skip>true</skip>
</configuration>
</plugin>
</plugins>
</build>

<repositories>
<repository>
<id>grails</id>
<name>grails</name>
<url>http://repo.grails.org/grails/core</url>
</repository>
</repositories>
</project>

我需要使用 groovy xml slurper 在上述 xml 文件中添加更多节点。例如:想要在现有的xml文件中添加以下配置。

<pluginRepositories>
<pluginRepository>
<id>synergian-repo</id>
<url>https://raw.github.com/synergian/wagon-git/releases</url>
</pluginRepository>
</pluginRepositories>

同样,我想在 dependency 元素中添加新的 dependency 元素:

<dependency>
<groupId>org.grails.plugins</groupId>
<artifactId>tomcat</artifactId>
<version>7.0.42</version>
<type>zip</type>
<scope>provided</scope>
</dependency>

我怎样才能实现这个目标?我查看了一些示例并编写了如下代码:

new File("pom.xml").withWriter('UTF-8') { w ->
def xml = new MarkupBuilder(w)
xml.pluginRepositories {
pluginRepository {
id "synergian-repo"
url "https://raw.github.com/synergian/wagon-git/releases"
}
}
}

但是上面的代码仅用新文本替换整个文件。

最佳答案

给你:

import groovy.xml.XmlUtil

def pom = '''
<?xml version="1.0" encoding="utf-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0">
<modelVersion>4.0.0</modelVersion>

<groupId>com.test.plugins</groupId>
<artifactId>testplugin</artifactId>
<packaging>grails-plugin</packaging>
<version>1.0</version>

<name>testplugin</name>
<description>testplugin</description>

<dependencies>
<dependency>
<groupId>org.grails</groupId>
<artifactId>grails-plugin-async</artifactId>
<version>${grails.version}</version>
</dependency>
</dependencies>

<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<configuration>
<skip>true</skip>
</configuration>
</plugin>
</plugins>
</build>

<repositories>
<repository>
<id>grails</id>
<name>grails</name>
<url>http://repo.grails.org/grails/core</url>
</repository>
</repositories>
</project>
'''

def xml = new XmlSlurper(false,false).parseText(pom)
xml.appendNode {
pluginRepositories {
pluginRepository {
id 'synergian-repo'
url 'https://raw.github.com/synergian/wagon-git/releases'
}
}
}
xml.dependencies.appendNode {
dependency {
groupId 'org.grails.plugins'
artifactId 'tomcat'
version '7.0.42'
type 'zip'
scope 'provided'
}
}
XmlUtil.serialize(xml)

关于xml - 修改 Groovy 中现有的 xml 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25386344/

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