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azure - 在 Azure 中创建 VM 时,虚拟网络可以位于不同的资源组中吗

转载 作者:行者123 更新时间:2023-12-02 04:27:56 27 4
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我想使用 powershell 在 Image1ABC 资源组中的 VM 上创建虚拟机,该资源组也在 ABC 资源组中。

现在我面临的问题是虚拟网络位于不同的资源组中,例如XYZ。所以我尝试了类似的方法,但没有成功。

$UserName = "admin"
$Password = ConvertTo-SecureString "admin@123" -AsPlainText -Force
$psCred = New-Object System.Management.Automation.PSCredential($UserName, $Password)
New-AzureRmVm `
-ResourceGroupName "ABC" `
-Name "VName" `
-ImageName "Image1" `
-Location "West US" `
-VirtualNetworkName "XYZ\Vnetname" `
-SubnetName "default" `
-Credential $psCred `
-OpenPorts 3389

我已经对此进行了搜索,但是如果您使用 Angular CLI 或从模板创建虚拟机,则有答案。但我想在没有模板的powershell中编写。

编辑

我已经尝试过,但无法继续

$UserName = "admin"
$Password = ConvertTo-SecureString "admin@123" -AsPlainText -Force
$Credential = New-Object System.Management.Automation.PSCredential($UserName, $Password)
$ResourceGroupName = "ABC"
$VMSize = "Standard_B2s"
$VMName = "VName1"
$LocationName = "West US"
$NICName = "VName123"
$VirtualNetworkName = "VNetName"
$VirtualNetworkResourceGroup = "XYZ"
$VnetAddressPrefix = "10.3.5.0/25"
$SubnetAddressPrefix = "10.3.5.0/25"
$SubnetName = "Subnet1"

$SingleSubnet = New-AzureRmVirtualNetworkSubnetConfig -Name $SubnetName -AddressPrefix $SubnetAddressPrefix
$Vnet = New-AzureRmVirtualNetwork -Name $VirtualNetworkName -ResourceGroupName $VirtualNetworkResourceGroup -Location $LocationName -AddressPrefix $VnetAddressPrefix -Subnet $SingleSubnet
$NIC = New-AzureRmNetworkInterface -Name $NICName -ResourceGroupName $VirtualNetworkResourceGroup -Location $LocationName -SubnetId $Vnet.Subnets[0].Id

$VirtualMachine = New-AzureRmVMConfig -VMName $VMName -VMSize $VMSize
$VirtualMachine = Set-AzureRmVMOperatingSystem -VM $VirtualMachine -Windows -ComputerName $VMName -Credential $Credential -ProvisionVMAgent -EnableAutoUpdate
$VirtualMachine = Add-AzureRmVMNetworkInterface -VM $VirtualMachine -Id $NIC.Id

New-AzureRmVM -ResourceGroupName $ResourceGroupName -Location $LocationName -VM $VirtualMachine -Verbose

$VnetAddressPrefix = "10.3.5.0/25"和 $SubnetAddressPrefix = "10.3.5.0/25"--> 不确定要输入什么。因此,我从 Azure 门户检查了 Subnet1 的 AddressRange,并输入了相同的值。

当我运行此命令时,它显示以下错误。

Cannot index into a null array.
At line:17 char:1
+ $NIC = New-AzureRmNetworkInterface -Name $NICName -ResourceGroupName ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : InvalidOperation: (:) [], RuntimeException
+ FullyQualifiedErrorId : NullArray

WARNING: New-AzureRmVMConfig: A property of the output of this cmdlet will change in an upcoming breaking change release. The StorageAccountType property for a DataDisk will return
Standard_LRS and Premium_LRS
WARNING: Set-AzureRmVMOperationSystem: A property of the output of this cmdlet will change in an upcoming breaking change release. The StorageAccountType property for a DataDisk will return
Standard_LRS and Premium_LRS
Add-AzureRmVMNetworkInterface : Cannot validate argument on parameter 'Id'. The argument is null or empty. Provide an argument that is not null or empty, and then try the command again.
At line:21 char:73
+ ... chine = Add-AzureRmVMNetworkInterface -VM $VirtualMachine -Id $NIC.Id
+ ~~~~~~~
+ CategoryInfo : InvalidData: (:) [Add-AzureRmVMNetworkInterface], ParameterBindingValidationException
+ FullyQualifiedErrorId : ParameterArgumentValidationError,Microsoft.Azure.Commands.Compute.AddAzureVMNetworkInterfaceCommand

WARNING: New-AzureRmVM: A property of the output of this cmdlet will change in an upcoming breaking change release. The StorageAccountType property for a DataDisk will return Standard_LRS and
Premium_LRS
WARNING: Error occurred when choosing existing standard storage account for boot diagnostics: Sequence contains no matching element
WARNING: Since the VM is created using premium storage, new standard storage account, corpcpscps082813020, is created for boot diagnostics.
VERBOSE: Performing the operation "New" on target "Vname1".
New-AzureRmVM : Required parameter 'networkProfile' is missing (null).
ErrorCode: InvalidParameter
ErrorMessage: Required parameter 'networkProfile' is missing (null).
StatusCode: 400
ReasonPhrase: Bad Request
OperationID : b1d281a7-a1df-48f6-9983-67319267f11d
At line:23 char:1
+ New-AzureRmVM -ResourceGroupName $ResourceGroupName -Location $Locati ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : CloseError: (:) [New-AzureRmVM], ComputeCloudException
+ FullyQualifiedErrorId : Microsoft.Azure.Commands.Compute.NewAzureVMCommand

最佳答案

是的,您可以在不同的资源组中使用 Vnet。但限制是您的 Vnet 和 VM 必须位于同一区域。

更新

使用 PowerShell cmdlet 在另一个资源组中使用 Vnet 创建虚拟机,您可以引用以下步骤。

  1. 使用命令 Get-AzureRmVirtualNetwork -ResourceGroupName vnetResourceGroupName -Name VnetName 获取另一个资源组中的 Vnet。
  2. 创建与 Vnet 关联的网络接口(interface)。
  3. 照常设置其他选项。
  4. 创建虚拟机。

以下脚本仅供引用。

$UserName = userName
$Password = ConvertTo-SecureString password -AsPlainText -Force
$psCred = New-Object System.Management.Automation.PSCredential($UserName, $Password)

New-AzureRmResourceGroup -Name resourceGroupName -Location location

$PIP = New-AzureRmPublicIpAddress -Name publicIPName -DomainNameLabel publicIPDomain -ResourceGroupName resourceGroupName -Location location -AllocationMethod Dynamic
$Vnet = $(Get-AzureRmVirtualNetwork -ResourceGroupName vnetResourceGroupName -Name VnetName)
$NIC = New-AzureRmNetworkInterface -Name NICNName -ResourceGroupName resourceGroupName -Location location -SubnetId $Vnet.Subnets[0].Id -PublicIpAddressId $PIP.Id

$VirtualMachine = New-AzureRmVMConfig -VMName vmName -VMSize vmSize
$VirtualMachine = Set-AzureRmVMOperatingSystem -VM $VirtualMachine -Windows -ComputerName conputerName -Credential $psCred -ProvisionVMAgent -EnableAutoUpdate
$VirtualMachine = Add-AzureRmVMNetworkInterface -VM $VirtualMachine -Id $NIC.Id

$VirtualMachine = Set-AzureRmVMSourceImage -VM $VirtualMachine -PublisherName 'MicrosoftWindowsServer' -Offer 'WindowsServer' -Skus '2012-R2-Datacenter' -Version latest
New-AzureRmVm -ResourceGroupName resourceGroupName -Location location -VM $VirtualMachine

关于azure - 在 Azure 中创建 VM 时,虚拟网络可以位于不同的资源组中吗,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52051134/

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