java - 检查数组中最大和最小元素的数量

Question

我试图检查给定数组是否具有相同数量的最大和最小数组元素。如果它们的数量相等，则应返回 1，否则返回 0。但通常返回 0。

你能帮我一下吗？

public class MaxMinEqual {

public static void main(String[] args) {


    System.out.println(MaxMinEqual.ismaxminequal(new int[]{11, 4, 9, 11, 8, 5, 4, 10}));
    System.out.println(MaxMinEqual.ismaxminequal(new int[]{11, 11, 4, 9, 11, 8, 5, 4, 10}));
}

public static int ismaxminequal(int[] a) {
    int maxcount = 0;
    int mincount = 0;
    int largest = a[0];

    for (int i = 0; i < a.length; i++) {

        if (a[i] > largest) {
            largest = a[i];
        }
        if (a[i] == largest) {
            maxcount = maxcount + 1;
        }

    }
    int smallest = a[0];

    for (int j = 0; j < a.length; j++) {

        if (a[j] < smallest) {
            smallest = a[j];
        }
        if (a[j] == smallest) {
            mincount = mincount + 1;
        }

    }
    if (maxcount == mincount) {
        return 1;
    } else {
        return 0;
    }
}
}

Answer 1

当您发现更大或更小的值时，您没有重置 maxcount 和 mincount。

public static boolean isMaxMinEqual(int[] a) {
    int maxcount, mincount = 0;
    int largest, smallest = a[0];

    for (int i = 0: a) {

        if (i > largest) {
            largest = i;
            maxcount = 0;
        }
        if (i == largest) {
            maxcount++;
        }

        if (i < smallest) {
            smallest = i;
            mincount = 0;
        }
        if (i == smallest) {
            mincount++;
        }

    }

    return maxcount == mincount;
}