java - 我在 JAVA 循环中遇到问题

Question

  import java.util.Scanner;
    public class Lab101{
        public static void main(String[]args){
        Scanner sc = new Scanner(System.in);  

     System.out.println("Enter Class Limit:");
     int x = sc.nextInt();

     for (char i=1; i<=x; i++) {
       System.out.println("Enter Student Name: ");
       sc.next().charAt(0);
     }

     System.out.println("Class Is Full");}}

Enter Class Limit:
3
Enter Student Name: 
Input
Enter Student Name: 
Name
Enter Student Name: 
Here
Class Is Full

现在我的问题已经解决了。但后来我发现了一个新问题!

Enter Class Limit:
3
Enter Student Name: 
Input Name
Enter Student Name: 
Enter Student Name: 
Here
Class Is Full

一旦我进入一个空间。算作一行输入两次，跳过第二行输入进入第三行。我如何让它接受一行中的空格并将其计为一行，以便我可以使其像这样......

Enter Class Limit:
3
Enter Student Name: 
Input Name Here
Enter Student Name: 
Input Name Here
Enter Student Name: 
Input Name Here
Class Is Full

Answer 1

您没有存储(或稍后显示)输入。我想你想两者都做。另外，如果您使用 nextInt() 读取 int，则必须使用 nextLine()。你可以使用 Arrays.toString(Object[])显示您的学生姓名(即字符串)。比如，

public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);

    System.out.println("Enter Class Limit:");
    int x = sc.nextInt();
    sc.nextLine(); // <-- there's a newline.
    String[] students = new String[x];
    for (int i = 0; i < x; i++) {
        System.out.printf("Enter Student Name %d: ", i + 1);
        System.out.flush();
        students[i] = sc.nextLine().trim();
    }

    System.out.println("Class Is Full");
    System.out.println(Arrays.toString(students));
}